Mass of (NH₄)₂U₂O₇ : 410.05 kg
<h3>Further explanation</h3>
Reaction
2UO₂SO₄ + 6NH₃ + 3H₂O → (NH₄)₂U₂O₇ + 2(NH₄)₂SO₄
MW UO₂SO₄ : 366.091
MW (NH₄)₂U₂O₇ : 624.131
MW H₂O : 18.0153
MW NH₃ : 17.0306
mol of 100 kg water :

mol of 100 kg ammonia :

mol of UO₂SO₄ :

Limiting reactants : smallest mol ratio(mol : coefficient)

UO₂SO₄ ⇒ Limiting reactants
mol (NH₄)₂U₂O₇ : mol UO₂SO₄

mass (NH₄)₂U₂O₇

Answer:
The value of N would be 4.
Explanation:
The equation would be 2n^x = 32 and therefore, 4.
The answers are I, II and IV
No matter how much water a human
drinks, the kidneys are always regulating various aspects of the blood,
including the pH of the blood, the plasma concentration of iron ions and the
plasma concentration of potassium ions.
Answer:
20 ounces of 14% solution and 8 ounces of 7% solution.
Explanation:
Let the amount of 14% solution required be A and the amount of 7% solution required be B.
Mixture of A and B must give 28 ounces:
A + B = 28 ................. Eqn 1
Also, mixture of 14% A and 7% B must give 12%, 28 ounces solution:
0.14A + 0.07B = 0.12(28) = 3.36...................Eqn 2
From eqn 1, B = 28 - A, eqn 2 becomes:
0.14A + 0.07(28 - A) = 3.36
0.07A = 3.36 - 1.96
A = 20 ounces
Substitute the value of A into eqn 1 to get B:
20 + B = 28
B = 8 ounces.
Hence, 20 ounces of 14% hydrochloric acid and 8 ounces of 7% hydrochoric acid should be mixed together in order to get 28 ounces of 12% solution.