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3 years ago

How many moles of carbon dioxide are produced from 148 g of acetylene

Chemistry

2 answers:

madreJ [45]3 years ago

4 0

Answer:- 11.4 g of $CO_2$ are produced by the combustion of 148 g of acetylene.

Solution:- Acetylene is a hydrocarbon that gives carbon dioxide on combustion in presence of oxygen. The balanced equation for the combustion of acetylene is:

$2C_2H_2+5O_2\rightarrow 4CO_2+2H_2O$

From balanced equation, there is 2:4 mol ratio between acetylene and carbon dioxide.

First of all we convert grams of acetylene to moles on dividing it's grams by molar mass of it. Then in next step, we multiply by mol ratio to get the moles of carbon dioxide.

Molar mass of acetylene is 26 . The set up would be as:

$148g C_2H_2(\frac{1molC_2H_2}{26g C_2H_2})(\frac{4 mol CO_2}{2mol C_2H_2})$

= 11.4 mol $CO_2$

So, 11.4 moles of $CO_2$ are produced by the combustion of 148 g of acetylene.

uysha [10]3 years ago

3 0

Nedd this too please helpppp

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The periodic table has mass units for every element that can be correlated with the number of atoms of that element. The relationship is known as Avogadro's Number. This number, 6.02x $10^{23}$ , is nicknamed the mole, which scientists found to be a lot more catchy, and easier to write than 6.02x $10^{23}$ . The mole is correlated to the atomic mass of that element. The atomic mass of sulfur, S, is 36.02 AMU, atomic mass units. But it can also be read as 36.02 grams/mole.

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This relationship holds for all the elements. Zinc, Zn, has an atomic mass of 65.38 AMU, so it has a "molar mass" of 65.38 grams/mole. ^5.38 grams of Zn contains 1 mole of Zn atoms.

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(5.0 moles S)*(36.02 grams/mole S) = 180.1 grams of S

Note how the units cancel to leaves just grams. The units are extremely helpful in mole calculations to insure the correct mathematical operation is done. To find the number of moles in 70 g of S, for example, we would write:

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