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3 years ago

How do you round sig figs

1 answer:

7 0

If its one significant figure, it means you round that number to the first digit for example 2457 to 1 significant figure will be 3000. Do you now how to round?

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Complete and balance the reaction in acidic solution. equation: ZnS + NO_{3}^{-} -> Zn^{2+} + S + NO ZnS+NO−3⟶Zn2++S+NO Which

kotykmax [81]

Answer:

Balanced reaction: $3ZnS+2NO_{3}^{-}+8H^{+}\rightarrow 3Zn^{2+}+3S+2NO+4H_{2}O$

S is oxidized and N is reduced.

$NO_{3}^{-}$ is the oxidizing agent and ZnS is the reducing agent.

Explanation:

Reaction: $ZnS+NO_{3}^{-}\rightarrow Zn^{2+}+S+NO$

$\Rightarrow$ Oxidation: $ZnS\rightarrow Zn^{2+}+S$

Balance charge: $ZnS-2e^{-}\rightarrow Zn^{2+}+S$ ...............(1)

$\Rightarrow$ Reduction: $NO_{3}^{-}\rightarrow NO$

Balance H and O in acidic medium : $NO_{3}^{-}+4H^{+}\rightarrow NO+2H_{2}O$

Balance charge: $NO_{3}^{-}+4H^{+}+3e^{-}\rightarrow NO+2H_{2}O$ ...............(2)

[ $3\times$ Equation-(1)] + [ $2\times$ Equation-(2)]:

$3ZnS+2NO_{3}^{-}+8H^{+}\rightarrow 3Zn^{2+}+3S+2NO+4H_{2}O$

Oxidation number of S increases from (-2) to (0) for the conversion of ZnS to S. Therefore S is oxidized.

Oxidation number of N decreases from (+5) to (+2) for the conversion of $NO_{3}^{-}$ to NO. Therefore N is reduced.

$NO_{3}^{-}$ consumes electron from ZnS. Therefore $NO_{3}^{-}$ is the oxidizing agent and ZnS is the reducing agent.

7 0

4 years ago

How many moles of potassium hydroxide are needed to completely react with 2.94 moles of aluminum sulfate according to the follow

fiasKO [112]

Answer:- Third choice is correct, 17.6 moles

Solution:- The given balanced equation is:

$Al_2(SO_4)_3+6KOH\rightarrow 2Al(OH)_3+3K_2SO_4$

We are asked to calculate the moles of potassium hydroxide needed to completely react with 2.94 moles of aluminium sulfate.

From the balanced equation, there is 1:6 mol ratio between aluminium sulfate and potassium hydroxide.

It is a simple mole to mole conversion problem. We solve it using dimensional set up as:

$2.94molAl_2(SO_4)_3(\frac{6molKOH}{1molAl_2(SO_4)_3})$

= 17.6 mol KOH

So, Third choice is correct, 17.6 moles of potassium hydroxide are required to react with 2.94 moles of aluminium sulfate.

8 0

4 years ago

How do you prove a scalene triangle is a right triangle?

Mrrafil [7]

if all sides are unequal it is scalene and if one angle adds up to 90 while the rest are different youve proven it.

3 0

3 years ago

What do the symbols in parenthesis indicate? C7H16 (l) + 11O2 (g) 7CO2 (g) + 8H2O (l) the physical state of each reactant and pr

Vadim26 [7]

The symbols indicate the physical state of each reactant

8 0

3 years ago

Read 2 more answers

The solubility of a solute and solvent at a given temperature is 30.65 g/100 mL.

Alisiya [41]

Answer:

613.0 g

Explanation:

2 L = 2000 mL

(30.65 g/100 mL)*2000 mL = 613.0 g

3 0

3 years ago

Read 2 more answers