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Anon25 [30]
4 years ago
5

Explain the property of velocity. Name one substance with high velocity.

Chemistry
2 answers:
mafiozo [28]4 years ago
7 0
Velocity is defined as displacement over time. Could you have possible meant viscosity? If so, viscosity is defined as the state of being thick, sticky, and semifluid in consistency, due to internal friction. And example of a substance with a high viscosity would be honey.
Tju [1.3M]4 years ago
6 0

Answer:

honey is the best substance with high velocity.

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Consider the following reaction mechanism: Step 1: (CH3)3AuPH3 ↔ (CH3)3Au + PH3 (fast) Step 2: (CH3)3Au → C2H6 + (CH3)Au (slow)
netineya [11]

Answer: The balanced equation for overall reaction is:

(CH3)3AuPH3 ----> C2H6 + (CH3)AuPH3

Explanation:

The reaction mechanism is given as follows:

Step 1: (CH3)3AuPH3 ↔ (CH3)3Au + PH3 (fast)

Step 2: (CH3)3Au → C2H6 + (CH3)Au (slow)

Step 3: (CH3)Au + PH3 → (CH3)AuPH3 (fast)

To balance this equation, firstly, we conduct proper atom count for each steps of the reaction mechanism.

It is important to note that for a reaction that involves several steps, the rate law is normally derived from the slow step ( which is step2 from the above mechanism).

Therefore, the balanced chemical equation for the overall reaction is:

(CH3)3AuPH3 ----> C2H6 + (CH3)AuPH3

7 0
3 years ago
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Oxygen has an atomic number of 8 and most commonly, a mass number of 16. thus, what is the atomic mass of an oxygen atom?
dexar [7]
Oxygen has atomic mass 16 amu
7 0
3 years ago
Write the equilibrium constant formula for the following reaction: 2H2+O2 yields 2H2O
Anvisha [2.4K]
2 H_{2} + O_{2} ---\ \textgreater \  2H_{2}O



K= \frac{ [H_{2}O]^{2} }{ [H_{2}]^{2} [O_{2}]}
8 0
3 years ago
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molecules that resemble fats but contain phosphate functional groups are called: a. steroids. b. polypeptides. c. phospholipids.
Rom4ik [11]
The answer is C. Phospholipids because Lipids mean "Fat"
8 0
3 years ago
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The rate at which a certain Australian tree cricket chirps is 194/min at 28°C, but only 47.6/min at 5°C, From these data calcula
uysha [10]

Answer: The energy of activation for the chirping process is 283.911 kJ/mol

Explanation:

According to the Arrhenius equation,

K=A\times e^{\frac{-Ea}{RT}}

The expression used with catalyst and without catalyst is,

\log (\frac{K_2}{K_1})=\frac{Ea}{2.303\times R}[\frac{1}{T_1}-\frac{1}{T_2}]

where,

K_2 = rate of reaction at 28^0C = 194/min

K_1 = rate of reaction at  5^0C = 47.6 /min

Ea = activation energy

R = gas constant = 8.314 J/Kmol

tex]T_1[/tex] = initial temperature = 5^oC=273+5=278K

tex]T_1[/tex] = final temperature = 28^oC=273+28=301K

Now put all the given values in this formula, we get

\frac{194}{47.6}=\frac{E_a}{2.303\times 8.314}[\frac{1}{278}-\frac{1}{301}]

{E_a}=283911J/mol=283.911kJ/mol

Thus the energy of activation for the chirping process is 283.911 kJ/mol

8 0
3 years ago
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