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Mnenie [13.5K]
3 years ago
12

What type of nuclear decay is shown by the reaction below?

Chemistry
2 answers:
Eva8 [605]3 years ago
6 0
Beta Decay - He atom is realeased
zysi [14]3 years ago
6 0

Can someone explain how to get the Th letters at the end I’ll how to

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What is one difference between an electron and a neutron?
VARVARA [1.3K]

Answer: Neutron has no charge, electron has a charge and mass. Neutron occurs inside the nucleus where electron is seen outside the nucleus.

Explanation:

5 0
3 years ago
How many grams of sucrose (c12h22o11) are in 1.55 l of 0.758 m sucrose solution? express your answer in grams to three significa
satela [25.4K]
The molecular formula of sucrose is - C₁₂H₂₂O₁₁
molecular mass of sucrose - 342 g/mol
molarity of sucrose solution is 0.758 M
In 1 L solution the number of sucrose moles are - 0.758 mol
Therefore in 1.55 L solution, sucrose moles are - 0.758 mol/L x 1.55 L
                                                                           = 1.17 mol
The mass of 1.17 mol of sucrose is - 1.17 mol x 342 g/mol = 4.00 x 10² g

7 0
3 years ago
Read 2 more answers
Suppose 0.981 g of iron (II) iodide is dissolved in 150. mL of a 35.0 m M aqueous solution of silver nitrate. Calculate the fina
yaroslaw [1]

Answer:

Final molarity of iodide ion C(I-) = 0.0143M

Explanation:

n = (m(FeI(2)))/(M(FeI(2))

Molar mass of FeI(3) = 55.85+(127 x 2) = 309.85g/mol

So n = 0.981/309.85 = 0.0031 mol

V(solution) = 150mL = 0.15L

C(AgNO3) = 35mM = 0.035M = 0.035m/L

n(AgNO3) = C(AgNO3) x V(solution)

= 0.035 x 0.15 = 0.00525 mol

(AgNO3) + FeI(3) = AgI(3) + FeNO3

So, n(FeI(3)) excess = 0.00525 - 0.0031 = 0.00215mol

C(I-) = C(FeI(3)) = [n(FeI(3)) excess]/ [V(solution)] = 0.00215/0.15 = 0.0143mol/L or 0.0143M

8 0
3 years ago
MgS is the chemical formula for the ionic compound named
irina1246 [14]

Answer:

Magnesium Chloride

Explanation:

3 0
3 years ago
Any integrated chem buffs out there?
marusya05 [52]

The field of study that Christian Doppler's work influenced the most was about <u>light </u><u>waves.</u>

Hope it helps you.

5 0
3 years ago
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