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Lady_Fox [76]
3 years ago
10

Please help me with this question, especially the angle part. I have solved the initial velocity already. I don't know what to d

o. Thank you.

Physics
1 answer:
Helga [31]3 years ago
5 0
I think you almost got it.

At the top, the velocity only has horizontal component, so v=12 m/s is v_x, which is v*cos(theta), because v_x is constant, so the same when it was launched or now.

With the value of the initial speed (28 m/s, which is the total speed), you can set

v_x = v * cos( theta ) ---> 12 = 28*cos(theta) --> cos(theta)=12/28=3/7

or theta = 64.62 deg, it is D. Think about it. I hope you see it.
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