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Degger [83]
3 years ago
15

Brownian motion is not observed in a mixture that includes two phases. Which best identifies the mixture? [A} a colloid

Chemistry
1 answer:
Hoochie [10]3 years ago
3 0

b, a suspension

Hope this helped :)

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For each pair, choose the compound with the smaller lattice energy, and explain your choice: (b) K₂O or K₂S.
dlinn [17]

the compound with the smaller lattice energy is potassium sulphide here the size of the molecule play a important role

The quantity of energy released by the electrostatic attraction of oppositely charged ions is known as lattice energy (L.E). The ion's size and charge affect the lattice energy.

lattice energy is inversely proportional to   size of ion and directly proportional to charge of the ion. They are each charged equally that is plus two and minus two However, because the Sulphur is larger in size  and the oxygen is lesser in this case, The lattice energy of potassium oxide is larger  the lattice energy of potassium sulphide  is smaller.

To learn more about lattice energy :

brainly.com/question/18222315

#SPJ4

5 0
1 year ago
Convert 5.28 x 1019 molecules of C6H1206 to grams.
nlexa [21]

Answer:

m=0.0158g

Explanation:

Hello there!

In this case, it is possible to comprehend these mass-particles problems by means of the concept of mole, molar mass and the Avogadro's number because one mole of any substance has 6.022x10²³ particles and have a mass equal to the molar mass.

In such a way, for C₆H₁₂O₆, whose molar mass is about 180.16 g/mol, the referred mass would be:

m=5.28x10^{19}molecules*\frac{1mol}{6.022x10^{23}molecules}*\frac{180.16g}{1mol}\\\\m=0.0158g

Best regards!

5 0
3 years ago
Concentrated hydrogen peroxide solutions are explosively decomposed by traces of transition metal ions (such as Mn or Fe): 2H2O2
zalisa [80]

Answer:

23.0733 L

Explanation:

The mass of hydrogen peroxide present in 125 g of 50% of hydrogen peroxide solution:

Mass=\frac {50}{100}\times 125\ g

Mass = 62.5 g

Molar mass of H_2O_2 = 34 g/mol

The formula for the calculation of moles is shown below:

moles = \frac{Mass\ taken}{Molar\ mass}

Thus, moles are:

moles= \frac{62.5\ g}{34\ g/mol}

moles= 1.8382\ mol

Consider the given reaction as:

2H_2O_2_{(aq)}\rightarrow2H_2O_{(l)}+O_2_{(g)}

2 moles of hydrogen peroxide decomposes to give 1 mole of oxygen gas.

Also,

1 mole of hydrogen peroxide decomposes to give 1/2 mole of oxygen gas.

So,

1.8382 moles of hydrogen peroxide decomposes to give \frac {1}{2}\times 1.8382 mole of oxygen gas. Moles of oxygen gas produced = 0.9191 molGiven: Pressure = 746 torr
The conversion of P(torr) to P(atm) is shown below:
[tex]P(torr)=\frac {1}{760}\times P(atm)

So,

Pressure = 746 / 760 atm = 0.9816 atm

Temperature = 27 °C

The conversion of T( °C) to T(K) is shown below:

T(K) = T( °C) + 273.15  

So,  

T₁ = (27 + 273.15) K = 300.15 K

Using ideal gas equation as:

PV=nRT

where,  

P is the pressure

V is the volume

n is the number of moles

T is the temperature  

R is Gas constant having value = 0.0821 L.atm/K.mol

Applying the equation as:

0.9816 atm × V = 0.9191 mol × 0.0821 L.atm/K.mol × 300.15 K

<u>⇒V = 23.0733 L</u>

8 0
3 years ago
Arrange the following oxides in order of increasing acidity.
zmey [24]

Answer:

Based on the Modern Periodic table, there is an increase in the electropositivity of the atom down the group as well as increases across a period. On comparing the electropositivities of the mentioned oxides central atom, it is seen that Ca is most electropositive followed by Al, Si, C, P, and S is the least electropositive.  

With the decrease in the electropositivity, there is an increase in the acidity of the oxides. Thus, the increasing order of the oxides from the least acidic to the most acidic is:  

CaO > Al2O3 > SiO2 > CO2 > P2O5 > SO3. Hence, CaO is the least acidic and SO3 is the most acidic.  

5 0
3 years ago
How many moles of water are there in 1.000 l at stp? assume the density of water is 1000 kg/m3?
EastWind [94]
Assume 1 liter = 1 kilogram of water = 1000 grams of water.

Part A)
MW of hydrogen is 1.008g/mol, and oxygen is 16.00g/mol.

Find the MW of water by
2*(1.008) + (16.00) = 18.016g/mol.

Convert 1000g H2O to moles :

(1000g H2O)*(1mol H2O / 18.016g H2O) = 55.51 mol

Part B)
Using the answer from part A and Avogadro's number:

(55.51mol)*(6.022*10^23) =

3.343*10^25 molecules.
Hope this is helpful
7 0
3 years ago
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