Answer:
See explanation
Explanation:
A. This is a neutralization reaction.
Molecular equation;
HBr(aq) + CsOH(aq) ---------> CsBr(aq) + H20(l)
Complete ionic equation;
H^+(aq) + Br^-(aq) + Cs^(aq) + OH^-(aq) --------> Cs^+(aq) + Br^- + H20(l)
Net ionic equation;
H^+(aq) + OH^-(aq) --------> H20(l)
B. This is a gas forming reaction;
H2SO4(aq) + Na2CO3(aq) ------->Na2SO4(aq) + H2O(l) + CO2(g)
Complete ionic equation;
2H^+(aq) + SO4^-(aq) + 2Na^+(aq) + CO3^2-(aq) ------->2Na^+(aq) + SO4^-(aq) + H2O(l) + CO2(g)
Net ionic equation;
2H^+(aq) + CO3^2-(aq) -------> + H2O(l) + CO2(g)
C. This a precipitation reaction
Molecular equation;
CdCl2(aq) + Na2S(aq) ------->CdS(s) + 2NaCl(aq)
Complete ionic equation;
Cd^2+(aq) + 2Cl^-(aq) + 2Na^+(aq) + S^2-(aq) ---------> CdS(s) + 2Na^+(aq) + 2Cl^-(aq)
Net ionic equation;
Cd^2+(aq) + S^2-(aq) ---------> CdS(s)
Answer:
50 mL; 7
Explanation:
By looking at the graph, the boundary point where the solution turns from acidic to basic appears at approximately 50 mL.
Because this is a titration between a strong acid and strong base, the pH of the equivalence point is always 7 (aka neutral).
Answer:
The answer is
<h2>1479.60 mL</h2>
Explanation:
In order to calculate the volume needed we use the formula
where
C1 is the concentration of the stock solution
V1 is the volume of the stock solution
C2 is the concentration of the diluted solution
V2 is the volume of thevdiluted solution
From the question
C1 = 1.45 M
V1 = 25 mL
C2 = 0.0245 M
So we have
We have the final answer as
<h3>1479.60 mL</h3>
Hope this helps you
First: enzymes
Second: small intestine
third: waste
The initial report of the team formed by PURE may contain findings similar to the processes used in the disinfection of the water. Usual cases of ammonia presence in water are due to chloramine disinfection process. Also, they should also look into the storage of their facility and the end user which may also have a window of contamination.
