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suter [353]
2 years ago
10

Which of the following symbol means a subtance is in water solutions?

Chemistry
1 answer:
tankabanditka [31]2 years ago
7 0

Answer:

a.) (aq)

Explanation:

(aq) means aqueous

so its in a solvent

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Type the correct answer in the box. Use numerals instead of words.
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The amount of energy transferred to the coin is 28.5 joules.







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Which will have the lowest boiling point between pure water, 0.5NacI, 1.0 NaCi or 2.0 NaCi?
Andru [333]

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pure water will have the lowest boiling point.

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In a chemical compound, would you expect an oxide ion to be joined with one atom of calcium or one atom of potassium? Why?
Soloha48 [4]

I know what you're asking but I don't think the question is stated properly. Technically, an atom will not join with an "oxide" ion; i.e., the oxide ion is an atom of oxygen to which two electrons have been added. An oxide ion will add to 2 K ions or 1 Ca ion. The K ion has lost just one electron so it takes two of them to equal the 2- charge on the oxide ion whereas the Ca ion has lost two electrons and it takes only one of them to equal the charge on the oxide ion.

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3 years ago
_____ The primary function of molecular membranes is the transport of ions and molecules into and out of cells. The movement of
ale4655 [162]
<h2>Active Transport </h2>

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5 0
3 years ago
What will be the final temperature of the solution in a coffee cup calorimeter if a 50.00 mL sample of 0.250 M HCl(aq) is added
padilas [110]

Answer:

21.21°C will be the final temperature of the solution in a coffee cup calorimeter.

Explanation:

HCl+NaOH\rightarrow H_2O+NaCl

\Delta H = enthalpy change = -57.2 kJ/mol of NaOH

Moles of sodium hydroxide = n

Molarity of the NaOH = 0.250 M

Volume of NaOH solution = V = 50.00 mL = 0.050 L

n=Molarity\times V=0.250 M\times 0.050 L= 0.0125 mol

Moles of HCl = n'

Molarity of the HCl= 0.250 M

Volume of HCl solution = V' = 50.00 mL = 0.050 L

n'=Molarity\times V=0.250 M\times 0.050 L= 0.0125 mol

Since 1 mole of Hcl reacts with 1 mole of NaoH. Then 0.0125 mole of HCl will react with 0.0125 mole of NaOH.

The enthalpy change during the reaction.

\Delta H=-\frac{q}{n}

q=\Delta H\times n=-57.2 kJ/mol \times 0.0125 mol= -0.715 kJ=-715 J

q = heat released on reaction= -715 J

now, we calculate the heat gained by the solution.:

Q= -q = -(-715 J) = 715 J

m = mass of the solution = ?

Volume of the solution formed by mixing, v = 50.00 ml + 50.00 mL = 100.00 mL

Density of the solution = density of water = d = 1 g/mL

mass=density\times volume=d\times v=1 g/ml \times 100.00 ml=100 g

m = 100 g

q = heat gained = ?

c = specific heat = 4.18 J/^oC

T_{f} = final temperature = ?

T_{i} = initial temperature = 19.50^oC

Q=mc\times (T_{f}-T_{i})

Now put all the given values in the above formula, we get:

715 J=100 g\times 4.18J/^oC\times (T_f-19.50)^oC

T_f=21.21 ^oC

21.21°C will be the final temperature of the solution in a coffee cup calorimeter.

5 0
3 years ago
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