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4 years ago

Which part of a circuit creates an electric force field that makes it possible for the circuit to work?

2 answers:

7 0

Here, Your answer would be option D) Voltage Source.

Charge flows from it in a particular direction, and a charge ( static or dynamic ) creates an electric field around it (can be experimentally observed by a test charge), whereas all the other options are appliances which needs current ( rate of flow of charge ) to work.

In short, Your correct Answer would be Option D)-Voltage Source.

Hope this helps!

allochka39001 [22]4 years ago

7 0

<span>Voltage source is the answer.</span>

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A guitar player tunes the fundamental frequency of a guitar string to 560 Hz. (a) What will be the fundamental frequency if she

lawyer [7]

Answer:

(a) if she increases the tension in the string is increased by 15%, the fundamental frequency will be increased to 740.6 Hz

(b) If she decrease the length of the the string by one-third the fundamental frequency will be increased to 840 Hz

Explanation:

(a) The fundamental, f₁, frequency is given as follows;

$f_1 = \dfrac{\sqrt{\dfrac{T}{\mu}} }{2 \cdot L}$

Where;

T = The tension in the string

μ = The linear density of the string

L = The length of the string

f₁ = The fundamental frequency = 560 Hz

If the tension in the string is increased by 15%, we will have;

$f_{(1 \, new)} = \dfrac{\sqrt{\dfrac{T\times 1.15}{\mu}} }{2 \cdot L} = 1.3225 \times \dfrac{\sqrt{\dfrac{T}{\mu}} }{2 \cdot L} = 1.3225 \times f_1$

$f_{(1 \, new)} = 1.3225 \times f_1 = (1 + 0.3225) \times f_1$

$f_{(1 \, new)} = 1.3225 \times f_1 =\dfrac{132.25}{100} \times 560 \ Hz = 740.6 \ Hz$

Therefore, if the tension in the string is increased by 15%, the fundamental frequency will be increased by a fraction of 0.3225 or 32.25% to 740.6 Hz

(b) When the string length is decreased by one-third, we have;

The new length of the string, $L_{new}$ = 2/3·L

The value of the fundamental frequency will then be given as follows;

$f_{(1 \, new)} = \dfrac{\sqrt{\dfrac{T}{\mu}} }{2 \times \dfrac{2 \times L}{3} } =\dfrac{3}{2} \times \dfrac{\sqrt{\dfrac{T}{\mu}} }{2 \cdot L} = \dfrac{3}{2} \times 560 \ Hz = 840 \ Hz$

When the string length is reduced by one-third, the fundamental frequency increases to one-half or 50% to 840 Hz.

6 0

3 years ago

The interest rate that the Fed charges banks that borrow money from it is called A. the discount rate. B. the federal rate. C. t

son4ous [18]

The answer is A. the discount rate.

7 0

3 years ago

Read 2 more answers

Material that slows down or resists the flow of current. these are used in electric circuits to help control the flow of current

Nataly_w [17]

It's called an insulator

3 0

3 years ago

A snail crawls at a speed of 0.0004 m/s. How long will ot take to climb a garden stick 1.6m high?

tekilochka [14]

4000 seconds

Explanation:

speed = distance / time

0.0004m/s = 1.6m / time

Subject time

time = 1.6 / 0.0004

time = 4000 seconds.

Hope this helps. Mark as brainliest if possible. tks

5 0

3 years ago

A bullet with kinetic energy of 400J strikes a wooden block where a 8.00x10N resistive force stops the bullet what is the penetr

tia_tia [17]

The "penetration of the bullet" is 5 m

<u>Explanation</u>:

A "bullet" with "kinetic energy" of = 400J

A resistive force stops the bullet = 8.00 x 10 N

Work = change in energy

Work = ∆ Kinetic Energy (equation 1)

Work = $F\times d$ (equation 2)

From equations 1 and 2 we have,

$F\times d$ = ∆ Kinetic Energy

Where ,

Kinetic Energy = 400 J

F = 8.00 x 10 N

(8.00 x 10 N) d = 400 J

(80 N) d = 400 J

$d=\frac{400}{80}$

d = 5 m

The penetration of the bullet is 5 m

5 0

3 years ago