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leonid [27]
4 years ago
12

How much heat is needed to change 1.25 kg of steak at 100°C to water at 100°C?

Physics
1 answer:
cricket20 [7]4 years ago
7 0

The heat required to change 1.25 kg of steak is 2825 kJ /kg.

<u>Explanation</u>:

Given, mass m = 1.25 kg,     Temperature t = 100 degree celsius

To calculate the heat required,

                                 Q = m \times L

where m represents the mass in kg,

          L represents the heat of vaporization.

When a material in the liquid state is given energy, it changes its phase from liquid to vapor and the energy absorbed in this process is called heat of the vaporization. The heat of vaporization of the water is about 2260 kJ/kg.

                                  Q = 1.25 \times 2260

                                  Q = 2825 kJ /kg.

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The acceleration due to gravity on Jupiter is 2.5 times what it is here on earth. An object weighing 347.9 N here on earth will
inessss [21]

Answer:  weight on Jupiter = 869.75 N

              mass  on Earth = mass on Jupiter = 35.5 Kg

Explanation:

W = mg

W = weight

m = mass

g = gravitational acceleration [ on the Earth, g₁ = 9,8 N/kg ]

On the Earth,

G₁ = m x g₁  = 347,9 N

On the Jupiter,

G₂ = mg₂  

mass on the Earth = mass on the Jupiter !  

m = G₁ : g = 347.9 N : 9,8 N/kg = 35.5 kg

G2 : G1 = 2.5

G₂ = 2,5 G₁ = 2,5 x 347.9 N =  869,75 N

5 0
4 years ago
What is a metallic bond and how does it hold metals together?
Marysya12 [62]

Answer:

Force that holds atoms together in a metallic substance.

Explanation:

Hope this helps? C:

~Chiena

4 0
2 years ago
15. How mh energy does a 850W microwave transfer reheating a meal for 30s?
VARVARA [1.3K]
Answer- is 10000000000
7 0
3 years ago
Read 2 more answers
Two long parallel wires carry currents of 20 A and 5.0 A in opposite directions. The wires are separated by 0.20 m. What is the
zzz [600]

The magnetic field midway between the two wires is 5.0*10^{-7} T.

It is given that Two long parallel wires carry currents of 20 A and 5.0 A in opposite directions. The wires are separated by 0.20 m.

We need to determine the magnetic field midway between the two wires.

A magnetic field is a vector field that describes the magnetic influence on moving electric charges, electric currents, and magnetic materials.

A moving charge in a magnetic field experiences a force perpendicular to its own velocity and to the magnetic field.

Magnetic field is a place in space near a magnet or an electric current where a physical field is created from a moving electric charge that creates force on another moving electric charge.

B=B1+B2

=\frac{4\pi *10^{-7}*20 }{2\pi R1} +\frac{4\pi *10^{-7}*5 }{2\pi R2}

= \frac{4\pi *10^{-7}*20 }{2\pi *0.10} +\frac{4\pi *10^{-7}*5 }{2\pi *0.10}

= 5.0*10^{-7} T

Hence, the magnetic field midway between the two wires is 5.0*10^{-7} T

Learn more about magnetic field click here, brainly.com/question/14848188

#SPJ4

3 0
2 years ago
How much heat is necessary to change 350 g of ice at -20 degrees Celsius to water at 20 Celsius?
sergejj [24]

Answer:

160790 J

Explanation:

We can find the heat necessary for the ice to go from -20 degrees Celsius to 0 degrees Celsius:

Q=mc\Delta t

Where c=2.09 J/g^{\circ}C is the specific heat of ice, that is the amount of heat that must be supplied per unit mass to raise its temperature in a unit.

Q=(350g)(2.09 J/g^{\circ}C)(0^{\circ}C-(-20^{\circ}C))=14630 J

We must calculate the latent heat of fusion required for this ice mass to change to water:

Q=mH

Where H=334 J/g is the specific latent heat of fusion of water, that is the amount of energy needed per unit mass of a substance at its melting point to change from the solid to the liquid state.

Q=(350g)(334 J/g)=116900 J

Then we calculate the heat necessary for the water to go from 0 degrees Celsius to 20 degrees Celsius:

Q=mc\Delta t

Where c=4.18 J/g^{\circ}C is the specific heat of water, that is the amount of heat that must be supplied per unit mass to raise its temperature in a unit.

Q=(350g)(4.18 J/g^{\circ}C)(20^{\circ}C-0^{\circ}C)=29260 J

Finally the 3 results are added:

Q_{T}=14630 J + 116900 J + 29260 J=160790 J

6 0
3 years ago
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