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3 years ago

Write the equations for the esterification process between ethanoic acid and 2-

Chemistry

1 answer:

Dafna11 [192]3 years ago

4 0

Answer: CH3COOH + CH3CHOHCH3 -> CH3COOCH(CH3)CH3 + H2O

Explanation: Estherification is the reaction between alkanoic acids and alkanols to porduce esters and what. ethanoic acid will react with 2-propanol to produce an ester and water.

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What do you think will happen to the kidneys if any of these parts were damaged?

Lemur [1.5K]

Answer:

<h3>When your kidneys are damage waste products and fluid can build up in your body. That can cause swelling in your ankles nausea weakness poor sleep and shortness of breath. so without treatement the damage can get worse and your kidney may eventually stop working.</h3>

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3 years ago

What is the percentage composition when 10g of magnesium combines with 4g of nitrogen?

Ivanshal [37]

The % composition when 10g of magnesium combine with 4g of nitrogen is 71.43% magnesium and 28.57 % nitrogen

calculation

% composition = mass of an element / total mass x100
mass of magnesium = 10 g
mass of nitrogen = 4g

calculate the total mass used

= 10g of Magnesium + 4 g of nitrogen = 14 grams

% composition for magnesium is therefore = 10/14 x100 = 71.43 %

% composition for nitrogen is therefore = 4 /14 x100 = 28.57 %

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3 years ago

Pls help me i dont know this

r-ruslan [8.4K]

Answer:

1. 12.6 moles

2. 8.95 moles

3. 2A + 5B → 3C

4. 48 moles

Explanation:

1. 2Fe + 3Cl₂ → 2FeCl₃

We assume the chlorine in excess. Ratio is 2:2

2 moles of Fe, can produce 2 moles of chloride

12.6 moles of Fe will produce 12.6 moles of chloride.

2. 2Fe + 3Cl₂ → 2FeCl₃

For the same reaction, first of all we need to convert the mass to moles:

500 g . 1mol / 55.85 g = 8.95 mol

As ratio is 2:2, the moles we have are the same, that the produced

4. The reaction for the combustion is:

2C₂H₆ (g) + 7O₂ (g) → 4CO₂ (g) + 6H₂O (l)

We assume the oxygen in excess.

Ratio is 2:6, so 2 mol of ethane produce 6 moles of water

Therefore 16 moles of ethane may produce (16 .6) / 2 = 48 moles

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3 years ago

Why will paper stick to a ballon that you have rubbed on your hair?

Usimov [2.4K]

Depending on the balloon, the surface will cause friction between the two and oxygen molecules will fuse together to create a sticky sensation

7 0

3 years ago

what is the limiting reactant when 1.50g of lithium and 1.50 g of nitrogen combine to form lithium nitride, a component of advan

PSYCHO15rus [73]

<h3>Answer:</h3>

Limiting reactant is Lithium

<h3>Explanation:</h3>

We are given;

Mass of Lithium as 1.50 g
Mass of nitrogen is 1.50 g

We are required to determine the rate limiting reagent.

First, we write the balanced equation for the reaction

6Li(s) + N₂(g) → 2Li₃N

From the equation, 6 moles of Lithium reacts with 1 mole of nitrogen.

Second, we determine moles of Lithium and nitrogen given.

Moles = Mass ÷ Molar mass

Moles of Lithium

Molar mass of Li = 6.941 g/mol

Moles of Li = 1.50 g ÷ 6.941 g/mol

= 0.216 moles

Moles of nitrogen gas

Molar mass of Nitrogen gas is 28.0 g/mol

Moles of nitrogen gas = 1.50 g ÷ 28.0 g/mol

= 0.054 moles

According to the equation, 6 moles of Lithium reacts with 1 mole of nitrogen.
Therefore, 0.216 moles of lithium will require 0.036 moles (0.216 moles ÷6) of nitrogen gas.
On the other hand, 0.054 moles of nitrogen, would require 0.324 moles of Lithium.

Thus, Lithium is the limiting reagent while nitrogen is in excess.

7 0

3 years ago