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shutvik [7]
3 years ago
5

Write the equations for the esterification process between ethanoic acid and 2-

Chemistry
1 answer:
Dafna11 [192]3 years ago
4 0

Answer: CH3COOH + CH3CHOHCH3 -> CH3COOCH(CH3)CH3 + H2O

Explanation: Estherification is the reaction between alkanoic acids and alkanols to porduce esters and what. ethanoic acid will react with 2-propanol to produce an ester and water.

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A chemist identifies compounds by identifying bright lines in their spectra. She does so by heating the compounds until they glo
allsm [11]

Answer:

PART A: 412.98 nm

PART B: 524.92 nm

Explanation:

The equation below can be used for a diffraction grating of nth order image:

n*λ = d*sinθ_{n}

Therefore, for first order images, n = 1 and:

λ = d*sinθ_{1}.

The angle θ_{1} can be calculated as follow:

tan θ_{1}  = 9.95 cm/15.0 cm = 0.663 and

θ_{1} = tan^{-1} (0.663) = 33.56°

Thus: d =λ/sin θ_{1}  = 461/sin 33.56° = 833.97 nm

PART A:

For a position of 8.55 cm:  

tan θ_{1}  = 8.55 cm/15.0 cm = 0.57 and

θ_{1} = tan^{-1} (0.57) = 29.68°

Therefore:

λ =d*sin θ_{1}  = 833.97*sin 29.68° = 412.98 nm

PART B:

For a position of 12.15 cm:  

tan θ_{1}  = 12.15 cm/15.0 cm = 0.81 and

θ_{1} = tan^{-1} (0.81) = 39.01°

Therefore:

λ =d*sin θ_{1}  = 833.97*sin 39.01° = 524.92 nm

6 0
3 years ago
What structure do all of these elements have in common?
r-ruslan [8.4K]
I think the answer is the number of protons.
8 0
4 years ago
According to your study unit, what's the payoff that keeps volunteers using their own time to help their communities?
klasskru [66]
C. It's so rewarding, people feel emotionally high and fulfilled when they're done.

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8 0
3 years ago
Consider the above unbalanced equation. What volume of CO2 is produced at 270. mm Hg and 38.5°C when 0.820 g of C4H8 reacts with
irinina [24]

Answer:

The volume of CO2 is 4.20 L

Explanation:

Step 1: Data given

Pressure = 270 mm Hg =  260 /760 = 0.355263 atm

Temperature : 38.5 °C = 311.65 K

Mass of C4H8 = 0.820 grams

Step 2: The balanced equation

C4H8 + 6O2 → 4CO2 + 4H2O

Step 3: Calculate moles C4H8

Moles C4H8 = mass C4H8 / molar mass C4H8

Moles C4H8 = 0.820 grams / 56.11 g/mol

Moles C4H8 = 0.0146 moles

Step 4: Caalculate moles CO2

For 1 mol C4H8 we need 6 moles O2 to produce 4 moles CO2 and 4 moles H2O

For 0.0146 moles we'll have 4*0.0146 = 0.0584 moles CO2

Step 6: Calculate Volume CO2

p*V = n*R*T

V = (n*R*T) /p

⇒ with V = the volume of CO2 = TO BE DETERMINED

⇒ with n = the moles of CO2 = 0.0584 moles

⇒ with R = the gas constant = 0.08206 L*atm / mol*K

⇒ with T = The temperature = 311.65 K

⇒ with p = the pressure = 0.355263 atm

V = (0.0584 * 0.08206 * 311.65) / 0.355263

V = 4.20 L

The volume of CO2 is 4.20 L

8 0
3 years ago
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