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3 years ago

Which substance is commonly used to produce biomass fuel?

Chemistry

1 answer:

Lorico [155]3 years ago

8 0

Answer:

Corn stalks

Explanation:

Biomass fuel is produced by living or once-living organisms.

The most common biomass fuels used for energy come from plants, such as corn and soy.

B is wrong. Yellowcake is a refined form of uranium ore.

C and D are wrong. Coal and natural gas are not biomass fuels.

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What are the four important steps needed to obtain accurate melting points on a mel-temp

AveGali [126]

Explanation:

1) refine the specimen into fine powder 2) place the smallest amount you can see in the capillary tube 3) set the voltage to increase exponentially to 200 below the predicted temperature, then adjust so that the temperature rises to 20 per minute 4) report the temperature at which the liquid first appears and the temperature at which the last crystal disappears.

3 0

3 years ago

What is the density of a substance that has a volume of 14 millimeters and a mass of 13.2 grams.

Contact [7]

Answer:

Explanation:

The density of a substance can be found by using the formula

$density = \frac{mass}{volume} \\$

From the question we have

$density = \frac{13.2}{14} \\ = 0.94285...$

We have the final answer as

Hope this helps you

6 0

2 years ago

The density of aluminum is 2.7 g/mL if I add a piece of aluminum to a graduated cylinder of water in the water level increases b

viva [34]

The answer would be 5.5g because you have to subtract 8.2 minus 2.7 and you get 5.5g so basically the answer is C.

8 0

3 years ago

Henry divides 1.060g by 1.0mlbto find the density of his water sample. How many significant figures should he include in the den

kykrilka [37]

<span>Henry divides 1.060 g by 1.0 mL to find the density of his water sample.
</span>He should include THREE significant figures in the density value that hereports.

3 0

2 years ago

A 1. 07 g sample of a noble gas occupies a volume of 363 ml at 35°c and 678 mmhg. Identify the noble gas in this sample. (r = 0.

Margaret [11]

The identity of the noble gas is the sample is Krypton

<h3>Ideal Gas law</h3>

From the question, we are to determine the identity of the noble gas in the sample

From the ideal gas equation, we have that

PV = nRT

∴ n = PV / RT

Where P is the pressure

V is the volume

n is the number of moles

R is the gas constant

and T is the temperature

From the given information,

P = 678 mmHg = 0.892105 atm

V = 363 mL = 0.363 L

R = 0.08206 L.atm/mol.K

T = 35 °C = 35 + 273.15 K = 308.15 K

Putting the parameters into the equation, we get

n = (0.892105 × 0.363)/ (0.08206 × 308.15)

n = 0.0128 moles

Now, we will determine the Atomic mass of the sample

Using the formula,

Atomic = Mass / Number of moles

Atomic mass of the substance = 1.07 / 0.0128

Atomic mass of the substance = 83.6 amu

The noble gas with the closest atomic mass to this value is Krypton.

Molar mass of Krypton = 83.798 amu

Hence, the identity of the noble gas is the sample is Krypton

Learn more on Ideal Gas law here: brainly.com/question/20212888

#SPJ12

4 0

2 years ago