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Semmy [17]
3 years ago
13

Which substance is commonly used to produce biomass fuel?

Chemistry
1 answer:
Lorico [155]3 years ago
8 0

Answer:

Corn stalks  

Explanation:

Biomass fuel is produced by living or once-living organisms.

The most common biomass fuels used for energy come from plants, such as corn and soy.

B is wrong. Yellowcake is a refined form of uranium ore.  

C and D are wrong. Coal and natural gas are not biomass fuels.

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Why is O2 necessary for rusting?
Charra [1.4K]

O2 isn't necessary for rusting, but some source of oxygen is required. Rust is just another name for iron oxide, and without oxygen there can't be oxide.

Hope this helps,

Davinia.

5 0
3 years ago
Read 2 more answers
Energy is the sum of kinetic energy + potential energy.
Rashid [163]

Answer:

electrical

Explanation:

they are working together

3 0
3 years ago
What is the molarity of a 0.250 L MgCl2 solution that contains 0.175 mol MgCl2?
spayn [35]

Explanation:

we know that 0.250 L = 0.250 dm3

molarity = concentration in dm3/ volume

molarity = 0.175/0.250 = 0.7 mol/dm3

4 0
3 years ago
A solution was prepared by dissolving 0.800 g of sulfur S8, in 100.0 g of acetic acid, HC2H3O2. Calculate the freezing point and
Romashka [77]

<u>Answer:</u> The freezing point of solution is 16.5°C and the boiling point of solution is 118.2°C

<u>Explanation:</u>

To calculate the molality of solution, we use the equation:

Molality=\frac{m_{solute}\times 1000}{M_{solute}\times W_{solvent}\text{ in grams}}

Where,

m_{solute} = Given mass of solute (S_8) = 0.800 g

M_{solute} = Molar mass of solute (S-8) = 256.52 g/mol

W_{solvent} = Mass of solvent (acetic acid) = 100.0 g

Putting values in above equation, we get:

\text{Molality of solution}=\frac{0.800\times 1000}{256.52\times 100.0}\\\\\text{Molality of solution}=0.0312m

  • <u>Calculation for freezing point of solution:</u>

Depression in freezing point is defined as the difference in the freezing point of water and freezing point of solution.

\Delta T_f=\text{freezing point of acetic acid}-\text{Freezing point of solution}

To calculate the depression in freezing point, we use the equation:

\Delta T_f=iK_fm

or,

\text{Freezing point of acetic acid}-\text{Freezing point of solution}=iK_fm

where,

Freezing point of acetic acid = 16.6°C

i = Vant hoff factor = 1 (for non-electrolyte)

K_f = molal freezing point depression constant = 3.59°C/m

m = molality of solution = 0.0312 m

Putting values in above equation, we get:

16.6^oC-\text{freezing point of solution}=1\times 3.59^oC/m\times 0.0312m\\\\\text{Freezing point of solution}=16.5^oC

Hence, the freezing point of solution is 16.5°C

  • <u>Calculation for boiling point of solution:</u>

Elevation in boiling point is defined as the difference in the boiling point of solution and freezing point of pure solution.

The equation used to calculate elevation in boiling point follows:

\Delta T_b=\text{Boiling point of solution}-\text{Boiling point of acetic acid}

To calculate the elevation in boiling point, we use the equation:

\Delta T_b=iK_bm

or,

\text{Boiling point of solution}-\text{Boiling point of acetic acid}=iK_fm

where,

Boiling point of acetic acid = 118.1°C

i = Vant hoff factor = 1 (for non-electrolyte)

K_f = molal boiling point elevation constant = 3.08°C/m

m = molality of solution = 0.0312 m

Putting values in above equation, we get:

\text{Boiling point of solution}-118.1^oC=1\times 3.08^oC/m\times 0.0312m\\\\\text{Boiling point of solution}=118.2^oC

Hence, the boiling point of solution is 118.2°C

8 0
3 years ago
A ball is rolled at a velocity of 3 m/s and rolls for 5 seconds. How far does<br> the ball roll? *
MrRa [10]

Answer 15m

Explanation: Distance =  Speed x Time

3 x 5 =15

6 0
3 years ago
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