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natali 33 [55]
4 years ago
12

if monochromatic light passes from water into air with an angle of incidence of 35 degress which characteristic of light will re

main the same
Physics
1 answer:
Kamila [148]4 years ago
7 0
Frequency will be same
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What are sound waves
EastWind [94]

Answer:  Sound waves are a waves of compression and rarefaction, by which sound is propagated in an elastic medium such as air.

Explanation:

In physics, sound is a vibration that propagates as an acoustic wave, through a transmission medium such as a gas, liquid or solid.

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3 years ago
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A VW beetle goes from zero to 27m/s in 7.6 seconds. What is the acceleration?
Firlakuza [10]
Initial speed(u)=0m/s
Final speed(v)= 27m/s
Time(t)=7.6s
Use the equation of motion: v = u + at
27 = 0 + a(7.6)
27/7.6 = a
a = 3.55 m/s^2  (3 s.f)


7 0
3 years ago
What Could be the control in an experiment to measure the effects of gas additives on fuel
alina1380 [7]
Well,

A control in an experiment would basically be the "normal" version of your test subjects.

In a drug testing experiment with people, the control group would be the people who don't take the drug.

In an experiment on the effects of salt on potatoes, the control group would be a potato without salt on it.

So in an experiment to measure the effects of gas additives on fuel, the control would be fuel without additives.
8 0
3 years ago
Which is the correct representation of the right-hand rule for a current flowing to the right?
Elza [17]

Answer:

The third image

Explanation:

The one with the thumb pointing to the right

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3 years ago
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In the mobile m1=0.42 kg and m2=0.47 kg. What must the unknown distance to the nearest tenth of a cm be if the masses are to be
LuckyWell [14K]

Complete Question

The complete question is shown on the first uploaded image

Answer:

Explanation:

From he question we are told that

    The first mass is   m_1 = 0.42kg

      The second mass is  m_2 = 0.47kg

From the question we can see that at equilibrium the moment about the point where the  string  holding the bar (where m_1 \ and \ m_2 are hanged ) is attached is zero  

   Therefore we can say that

               m_1 * 15cm  = m_2 * xcm

Making x the subject of the formula  

                x = \frac{m_1 * 15}{m_2}

                    = \frac{0.42 * 15}{0.47}

                     x = 13.4 cm

Looking at the diagram we can see that the tension T  on the string holding the bar where m_1  \  and   \ m_2 are hanged  is as a result of the masses (m_1 + m_2)

     Also at equilibrium the moment about the point where the string holding the bar (where (m_1 +m_2)  and  m_3 are hanged ) is attached is  zero

   So basically

          (m_1 + m_2 ) * 20  = m_3 * 30

          (0.42 + 0.47)  * 20 = 30 * m_3

 Making m_3 subject

          m_3 = \frac{(0.42 + 0.47) * 20 }{30 }

                m_3 = 0.59 kg

3 0
3 years ago
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