The final speed of the orange is 7.35 m/s
Explanation:
The motion of the orange is a free fall motion, since there is only the force of gravity acting on it. Therefore, it is a uniformly accelerated motion with constant acceleration
towards the ground. So we can use the following suvat equation:

where
v is the final velocity
u is the initial velocity
a is the acceleration
t is the time elapsed
For the orange in this problem, we have
u = 0 (it is dropped from rest)
is the acceleration
Substituting t = 0.75 s, we find the final velocity (and speed) of the orange:

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Answer:
P = 147,75 W
Explanation:
A man whose mass is 59.1kg climbs up 30 steps of a stair each step is 25 cm high
Height at 30 steps , h=30×2.5= 7.5 m
Change in potential energy , =mgh=59.1×10×7.5 = 4432.5 J
So, Work done by the man , W= 4432.5J
Power used , P= 
P = 4432.5 /30
P = 147,75 W
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Newton’s Law: F = MA
A = F/M (change equation)
12.6 N/ 2.4 kg = 5.25
Answer: acceleration is 5.25 m/s^2
I think its E. the control rods are used to control <span>the fission rate of uranium and plutonium. Hope this helps!! </span>
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13 g —> 0.013 kg
KE = 1/2(m)(v)^2
KE = 1/2(0.013)(8.5)^2
KE = 0.47 J