Answer:
a)
840 N
b)
10920 J
c)
- 10192 J
d)
4.3 m/s
Explanation:
a)
T = tension force in the cable in upward direction = ?
a = acceleration of the person in upward direction = 0.70 m/s²
m = mass of the person being lifted = 80 kg
Force equation for the motion of person in upward direction is given as
T - mg = ma
T = m (g + a)
T = (80) (9.8 + 0.70)
T = 840 N
b)
d = distance traveled in upward direction = 13 m
= Work done by tension force
Work done by tension force is given as
= T d
= (840) (13)
= 10920 J
c)
d = distance traveled in upward direction = 13 m
= Work done by person's weight
Work done by person's weight is given as
= - mg d
= - (80 x 9.8) (13)
= - 10192 J
d)
= Net force on the person = ma = 80 x 0.70 = 56 N
v₀ = initial speed of the person = 0 m/s
v = final speed
Using work-energy theorem
d = (0.5) m (v² - v₀²)
(56) (13) = (0.5) (80) (v² - 0²)
v = 4.3 m/s
Answer:
here you go
Explanation:
1. With a battery load tester, apply a load equal to one-half of the CCA rating of the battery for 15 seconds. ...
2. With a battery load tester, apply a load equal to one-half the vehicle's CCA specification for 15 seconds.
3. Disable the ignition and turn the engine over for 15 seconds with the starter motor.
It's called condensation. That is what that wetness on the outside of the cup is.
Answer:
h = 81.63 m
Explanation:
Given that,
The speed of the car, v = 40 m/s
We need to find the height when the car comes to rest. We can use the conservation of energy to find it i.e.

So, it will reach to a height of 81.63 m and comes to rest.
Answer: 0.5N
Explanation:
Gravitational force is calculated using the formula :
F = Gm1m2/r^2
Where G is the gravitational constant (6.67 × 10^-11)
At a distance 'r' of 2metres apart:
Mass of objects are m1 and m2
Gravitational force 'F1' = 2N
Inputting values into the formula :
2 = Gm1m2 / 2^2 - - - - - (1)
At a distance 'r' of 4meters apart:
Mass of objects are m1 and m2
Gravitational force 'F2' = y
Inputting values
F2 = Gm1m2 / 4^2 - - - - - (2)
Dividing equations 1 and 2
2 = Gm1m2 / 2^2 ÷ F2 = Gm1m2 / 4^2
2 / F2 = (Gm1m2 / 4) / (Gm1m2 / 16)
2 / F2 = (Gm1m2 / 4) × (16 / Gm1m2)
2/F2 = 16 / 4
Cross multiply
2 × 4 = 16 × F2
8 = 16F2
F2 = 8/16
F2 = 0.5N