An elevator (mass 4000 kg) is to be designed so that the maximum acceleration is 0.0500g. what is the maximum force the motor sh
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Answer: 25.7m/s
Explanation: the cars have equal masses so we only consider their velocities,
The cars traveled together at 65° north of east this is with a velocity equal to the resultant velocity,
Using the force diagram as shown below;
Tan 65° = Vn/Ve
Ve is velocity of the car traveling east
Vn is velocity of car traveling north
Tan 65° = V2/12
2.144 = V2/12
V2 = 12 * 2.144
V2 = 25.7 m/s
