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Bumek [7]
4 years ago
7

An elevator (mass 4000 kg) is to be designed so that the maximum acceleration is 0.0500g. what is the maximum force the motor sh

ould exert on the supporting cable?
Physics
1 answer:
Alex4 years ago
4 0

The formula relating mass, force and acceleration is:

Force = mass * acceleration

Therefore to calculate the maximum force, simply multiply the two: (g = gravity = 9.8 m/s^2)

Force = 4000 kg * 0.0500 (9.8 m / s^2)

<span>Force = 1960 Newton</span>

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The person has an upward acceleration of 0.70 m/s^2 and is lifted from rest through a distance of 13 m. A rescue helicopter lift
Alex

Answer:

a)

840 N

b)

10920 J

c)

- 10192 J

d)

4.3 m/s

Explanation:

a)

T = tension force in the cable in upward direction = ?

a = acceleration of the person in upward direction = 0.70 m/s²

m = mass of the person being lifted = 80 kg

Force equation for the motion of person in upward direction is given as

T - mg = ma

T = m (g + a)

T = (80) (9.8 + 0.70)

T = 840 N

b)

d = distance traveled in upward direction = 13 m

W_{t} = Work done by tension force

Work done by tension force is given as

W_{t} = T d

W_{t} = (840) (13)

W_{t} = 10920 J

c)

d = distance traveled in upward direction = 13 m

W_{g} = Work done by person's weight

Work done by person's weight is given as

W_{g} = - mg d

W_{g} = - (80 x 9.8) (13)

W_{g} = - 10192 J

d)

F_{net} = Net force on the person = ma = 80 x 0.70 = 56 N

v₀ = initial speed of the person = 0 m/s

v = final speed

Using work-energy theorem

F_{net} d = (0.5) m (v² - v₀²)

(56) (13) = (0.5) (80) (v² - 0²)

v = 4.3 m/s

6 0
4 years ago
When performing a battery load test, what should the load be set to?​
ASHA 777 [7]

Answer:

here you go

Explanation:

1. With a battery load tester, apply a load equal to one-half of the CCA rating of the battery for 15 seconds. ...

2. With a battery load tester, apply a load equal to one-half the vehicle's CCA specification for 15 seconds.

3. Disable the ignition and turn the engine over for 15 seconds with the starter motor.

3 0
3 years ago
Why do you think the cup that is exposed to more air has water outside it?
mylen [45]
It's called condensation. That is what that wetness on the outside of the cup is.
6 0
3 years ago
PLEASE HELP AS SOON AS POSSIBLE!!!
Brums [2.3K]

Answer:

h = 81.63 m

Explanation:

Given that,

The speed of the car, v = 40 m/s

We need to find the height when the car comes to rest. We can use the conservation of energy to find it i.e.

mgh=\dfrac{1}{2}mv^2\\\\h=\dfrac{v^2}{2g}\\\\h=\dfrac{(40)^2}{2\times 9.8}\\\\h=81.63\ m

So, it will reach to a height of 81.63 m and comes to rest.

7 0
3 years ago
two masses are kept 2 metre apart there is gravitational force of 2 Newton what is the gravitational force when they are kept at
sukhopar [10]

Answer: 0.5N

Explanation:

Gravitational force is calculated using the formula :

F = Gm1m2/r^2

Where G is the gravitational constant (6.67 × 10^-11)

At a distance 'r' of 2metres apart:

Mass of objects are m1 and m2

Gravitational force 'F1' = 2N

Inputting values into the formula :

2 = Gm1m2 / 2^2 - - - - - (1)

At a distance 'r' of 4meters apart:

Mass of objects are m1 and m2

Gravitational force 'F2' = y

Inputting values

F2 = Gm1m2 / 4^2 - - - - - (2)

Dividing equations 1 and 2

2 = Gm1m2 / 2^2 ÷ F2 = Gm1m2 / 4^2

2 / F2 = (Gm1m2 / 4) / (Gm1m2 / 16)

2 / F2 = (Gm1m2 / 4) × (16 / Gm1m2)

2/F2 = 16 / 4

Cross multiply

2 × 4 = 16 × F2

8 = 16F2

F2 = 8/16

F2 = 0.5N

7 0
3 years ago
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