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Nataliya [291]
3 years ago
6

Sean, after being so happy for two full days that he reported he "never needed much sleep," now is stating he is so sad that he

cannot stop crying. Sean has
A) major depressive disorder
B) generalized anxiety disorder
C) obsessive-compulsive disorder
D) bipolar disorder
Physics
2 answers:
Kaylis [27]3 years ago
5 0
D or A i'm not that sure
VMariaS [17]3 years ago
4 0

it's Bipolar disorder

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Montano1993 [528]
Washington, or D.C.
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3 years ago
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1) Use SolidWorks (SW) FEA to apply a bending load of 600 lbf on the right end of the stepped shaft as shown below. This is the
salantis [7]

Solution :

Given :

L = 1 in

d = 0.75 in

D = 1 in

Fillet radius, r = 0.063 in

$K_{t_{bending}=\frac{\sigma_{FEA_{bending }}}{\sigma_{Nominal_{bending }}}$

We know that :

$\sigma_{b} = \frac{32M}{\pi d^3}$

$\sigma_{b} = \frac{32 \times (2998.63 \times 25.4)}{\pi (0.75 \times 25.4)^3}$

    $=112.27 \ N/mm^2$

$\sigma_{FEA} = 1.3 \times 10^8 \ N/m^2$

         $=1.3 \times 10^8 \times 10^{-6}$

         $=1.3 \times 10^2$   MPa

         = 130 MPa

Therefore, the stress concentration factor is :

$k_t=\frac{130}{112.27}$

   = 1.157922

8 0
3 years ago
The direction of a force can be represented by the length of an arrow.<br> True<br> False
natima [27]
True is The answer would be I just did this
4 0
3 years ago
Ohms law in symbols is
serious [3.7K]

Answer:

The potential difference across a given given wire of an circuit is directly proportional to the current flowing through it provided it's temperature remains the same. This is known as ohm's law

V is proportional to I

V/I = constant

V/I = R

V = IR where R is the constant of proportionality and resistance of the wire

Hope this helps!

6 0
3 years ago
In the Olympic shot-put event, an athlete throws the shot with an initial speed of 12.0 m/s at a 40.0 ∘ angle from the horizonta
Gre4nikov [31]

Answer:

Explanation:

given,

initial speed of the shot = 12.0 m/s

angle = 40°

height at which shot leaves her hand = 1.80 m

v_x = 12 cos 40° = 9.19 m/s

v_y = 12 sin 40° = 7.71 m/s

time to reach maximum height =

     = \dfrac{v_y}{g}

     = \dfrac{7.71}{9.8}

     = 0.787 s

h = v_y t + \dfrac{1}{2}gt^2

h = 7.71 × 0.787 - 0.5 × 9.81 × 0.787²

h = 3.03 m

the maximum height attain = 3.03 + 1.8 = 4.83 m

now free fall from the maximum height

h =\dfrac{1}{2}gt^2

4.83 = \dfrac{1}{2}\times 9.8 \times t^2

t = 0.9928 s

total time = 0.9928 + 0.787 = 1.7798 s

range =

d = vₓ t

d = 16.36 m

8 0
4 years ago
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