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iris [78.8K]
3 years ago
5

In oxidative phosphorylation, electrons are passed from one electron carrier to another. The energy released is used to ________

__. a. generate large amounts of NADH and FADH2 b. synthesize carbon dioxide c. pump protons (H⁺) across the mitochondrial membrane d. form ATP during glycolysis
Chemistry
1 answer:
Zepler [3.9K]3 years ago
7 0

Answer:

d. Form ATP during glycolysis.

Explanation:

During oxidative phosphorylation, an oxidation-reduction reactions will happen and the electrons transferred and energy released will be used in the conversion of adenosine diphosphate (ADP) into adenosine triphosphate (ATP).

This happens as a step of glycolysis, wich is the process in which the organism breaks gluscose molecules to obtain energy.

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HELP<br> How can you tell if mass is being conserved
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0. A liquid solution of LiCl in water at 25°C contains 1 mol of LiCl and 7 mol of water. If 1 mol of LiCl⋅3H2O(s) is dissolved i
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Answer:

19.488 kJ

Explanation:

The overall reaction mechanism shows the reaction between LiCl and H₂O

LiCl.3H_2O ------> Li +\frac{1}{2} Cl_2+3H_2+\frac{3}{2} O_2     -------- (1)

2Li+Cl_2+10H_2O ----->LiCl.10H_2O              -------- (2)

3H_2+\frac{3}{2}O_2 -----> 3H_2O                                     --------- (3)

LiCl.7H_2O ------>  Li + \frac{1}{2} Cl_2+7H_20             ---------- (4)

The overall reaction =

LiCl.7H_2O +LiCl.3H_2O ------>  2LiCl.10H_2O

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The overall enthalpy change is:

\delta H = \delta H _{LiCl.3H_2O}+\delta H_{3H_2O}  + \delta  H_{2(LiCl.5H_2O)} + \delta  H _{liCl.7H_2O}

\delta H =Q at constant pressure;

Thus; Q = 1311.3 (kJ)  857.49 (kJ) -873.61 (kJ) + 439.288 (kJ)

Q = 19.488 kJ

Thus, the heat effect = 19.488 kJ after the addition of  1 mol of LiCl⋅3H2O(s)

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