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Fittoniya [83]
4 years ago
6

The increases in a planet's speed as it approaches the sun is described by kepler's second law what is the best explanation for

this empirical law
Physics
1 answer:
Keith_Richards [23]4 years ago
5 0
<span>Keplers second law, that gravitational potential energy is lost when planets get near the sun and it becomes kinetic energy, best describes the reason why a planets speed will increase as it becomes closer to the sun.</span>
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Which two statements are scientific claims?
slavikrds [6]

Answer:

c.an equation that can be used to accurately calculate the pull of gravity between two objects

Explanation:

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6 0
3 years ago
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The height of an object dropped from the top of a 64-foot building is given by h(t)=-16t^2+64. How long will it take the object
mojhsa [17]

Answer:

1.86 s

Explanation:

Given the expression

h(t) = -16t²+ 64...................... Equation 1

Where h = height of the object, t = time it will take the object to hit the ground.

Given: h = 64 foot.

We have to concert from foot to meters

If 1 foot =  0.3048 meters

Then, 64 foot = 0.3048×64 = 19.51 meters.

We substitute the value of h into equation

119.51 = -16t²+64

-16t² = 199.51-64

-16t² = 55.51

t² = 55.51/-16

t² = 3.469

t = √3.469

t = 1.86 s.

Hence it will take the object 1.86 s to hit the ground.

7 0
3 years ago
An electric toaster has a power rating of 1100 W at 110 V. What is the resistance of the heating coil?
Semmy [17]

 R = 11 ohms

Explanation:

Given parameters:

Power of the electric toaster = 1100W

Voltage = 110V

Unknown:

Resistance, R of the heating coli = ?

Solution:

Electric power is given as:

     Electric power = IV

where:

  I is the current

  V is the voltage

       According to Ohm's law, V = IR

 where R is the resistance. If we make current the subject of the formula and substitute, it gives:

                  Power = \frac{[tex]V^{2}}{R}[/tex]

  Power =  \frac{[tex]110^{2}}{R}[/tex]

     R = \frac{Power }{[tex]110^{2}}[/tex] =  \frac{1100 }{[tex]110^{2}}[/tex]

   R = 11 ohms

learn more:

Power supply brainly.com/question/4322575

#learnwithBrainly

3 0
3 years ago
If a machine has an efficiency of 94% and you apply 574J of work, how much work do you get out of the machine
Mariana [72]
<h3>Answer:</h3>

539.56 Joules

<h3>Explanation:</h3>
  • Efficiency of a machine is the ratio of work output to work input expressed as a percentage.
  • Efficiency = (work output/work input) × 100%
  • Efficiency of a machine is not 100% because so energy is lost due to friction of the moving parts and also as heat.

In this case;

Efficiency = 94%

Work input = 574 Joules

Therefore, Assuming work output is x

94% = (x/574 J) × 100%

0.94 = (x/574 J)

<h3>x = 539.56 J</h3>

Thus, you get work of 539.56 J from the machine

7 0
3 years ago
An aerobatic airplane pilot experiences weightlessness as she passes over the top of a loop the loop maneuver. The acceleration
Natali5045456 [20]

The radius of the loop is 18.9 km

Explanation:

When the airplane is at the top of the loop, the pilot experiences two forces:

  • The force of gravity, acting downward, of magnitude mg
  • The normal reaction exerted by the seat on the pilot, also acting  downward, N

Since the plane is moving in a circular motion, the net force on the pilot must be equal to the centripetal force, therefore we can write:

mg+N = m\frac{v^2}{r}

where

m is the mass of the pilot

g=9.8 m/s^2 is the acceleration of gravity

N is the normal reaction

v = 430 m/s is the speed of the plane

r is the radius of the loop

Here we are told that the pilot feel weightless at the top of the loop: this means that the normal reaction is zero,

N = 0

Therefore the equation becomes

mg=\frac{mv^2}{r}

And so we can find the radius of the loop:

r=\frac{v^2}{g}=\frac{430^2}{9.8}=18.9 \cdot 10^3 m = 18.9 km

Learn more about circular motion:

brainly.com/question/2562955

brainly.com/question/6372960

#LearnwithBrainly

8 0
3 years ago
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