Question

How fast (in rpm) must a centrifuge rotate if a particle 5.50 cm from the axis of rotation is to experience an acceleration of 119000 g's? If the answer has 4 digits or more, enter it without commas, e.g. 13500.

Answer 1

Answer:

The velocity angular must be:

$w=43994rpm$

Explanation:

The definition of the centripetal acceleration is:

$a_c=w^2*r$

where, w, is the angular velocity

we solve in order to find w:

$w=\sqrt{a_c/r}=\sqrt{119000*g/0.055}=\sqrt{119000*9.81/0.055}=4607rad/s\\w=4607rad/s*(1 revolution/(2\pi*rad))*(60s/1mn)=43994rpm$