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dezoksy [38]
4 years ago
5

How to do this question?​

Physics
2 answers:
marissa [1.9K]4 years ago
7 0

Answer:

i3 =11.014A

i5 = 3.15A

Explanation:

Here according to k'chofs first law

i1 =i2 + i3

i3 = i4 + i5

For determine the i1 you have to consider the resultant resistor of the system

4 , 1 and 3 resistors are in pararel

Then, Resultant is

1/4 + 1/1 + 1/3 = 1/ R

R = 12/19

For get total we have to add another remaining 3 resistor because of serious

Then Resultant is = 12/19 + 3

= 69/19

Then using V = IR

40 =i3* 69/19

i3 = 11.014 A

Other 3 resistors are parrarel because of this voltage of those resistors are same.

Then i inversely propotional to its resistor

Then ,

i5 * 2 = (i3-i5)*4/5

i 5 = 3.15 A

Diano4ka-milaya [45]4 years ago
6 0

Answer:

I₁ = 11.2 A

I₂ = 1.6 A

I₃ = 9.6 A

I₄ = 6.4 A

I₅ = 3.2 A

Explanation:

Find the equivalent resistances.

Resistors 4 and 5 are in parallel:

R₄₅ = 1 / (1/R₄ + 1/R₅)

R₄₅ = 1 / (1/1 + 1/2)

R₄₅ = 2/3

Resistor 2 is in parallel with that:

R₂₄₅ = 1 / (1/R₂ + 1/R₄₅)

R₂₄₅ = 1 / (1/4 + 3/2)

R₂₄₅ = 4/7

Resistor 1 is in series with that:

R = R₁ + R₂₄₅

R = 3 + 4/7

R = 3 4/7

Now use Ohm's law to find I₁.

V = I₁ R

40 V = I₁ (3 4/7)

I₁ = 11.2 A

Find the voltage drop across R₁:

V₁ = I₁ R₁

V₁ = (11.2 A) (3 Ω)

V₁ = 33.6 V

So the voltage after is 40 V − 33.6 V = 6.4 V.

Find I₂:

6.4 V = I₂ (4 Ω)

I₂ = 1.6 A

Find I₃:

6.4 V = I₃ (2/3 Ω)

I₃ = 9.6 A

Find I₄:

6.4 V = I₄ (1 Ω)

I₄ = 6.4 A

Find I₅:

6.4 V = I₅ (2 Ω)

I₅ = 3.2 A

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Light of wavelength 650 nm is normally incident on the rear of a grating. The first bright fringe (other than the central one) i
garik1379 [7]

Answer

given,

wavelength (λ) = 650 nm

angle = 5°

using bragg's law

sin \theta = \dfrac{n \lambda}{d}

d= \dfrac{n \lambda}{sin \theta}

d= \dfrac{1 \times 650 \times 10^{-9}\ m}{sin5^0}

d = 7.46 x 10⁻⁴ cm

number of slits per centimeter

  = \dfrac{1}{d}\\\Rightarrow \dfrac{1}{7.46\times 10^{-4}}\\\Rightarrow 1340 split per centimeter.

b) wavelength of two rays  650 nm and 420 nm

 d = \dfrac{1}{5000}

     d =  2 x 10⁻6 m

    we now,

sin \theta = \dfrac{n \lambda}{d}

for 650 nm

sin \theta = \dfrac{2\times 650\times 10^{-9}}{2\times 10^{-6}}

\theta =sin^{-1}(0.65)

θ = 40.54°

for 450 nm

sin \theta = \dfrac{2\times 450\times 10^{-9}}{2\times 10^{-6}}

\theta =sin^{-1}(0.45)

θ = 24.83°

now, difference

|θ_{650} -θ_{420}| =40.54°-24.83°

|θ_{650} -θ_{420}| =19.71°

8 0
4 years ago
Why Are Atoms Neutral?
Pachacha [2.7K]
Answer is C.  when protons are equal to electrons their charges cancel out making it neutral because electrons have a charge of negative one and when you combine  them   positive 1 and negative 1 is 0.

5 0
3 years ago
Students are using the experimental setup shown in the image in which the two ends of a string are attached to a car and to a ha
AlekseyPX

The Newton's second law and kinematics allows to find the result of the error when placing the masses in the car is:

  • Acceleration decreases.
  • The plot of position vs. time squared is still linear, but the slope is less.

     

Newton's second law gives a relationship between the net force, mass and acceleration of the body

      F = ma

      a = \frac{F}{m}

Where F is the force, m the mass and the acceleration

 

Kinematics studies the motion of bodies, looking for relationships between position, velocity, and acceleration.

         x = v₀ t + ½ a t²

In the experiment, the position and time of the car are measured, starting from rest in each experiment.

        x = ½ a t²

Let's substitute

      x =  ½ ( \frac{F}{m} ) t²

This is the equation that the students should graph, a graph of the position versus time squared can be made to obtain a line.

The slope of the line is the acceleration of the car, which is related to the force that is the weight of the hanging mass.

When the student makes the mistake of placing the mass on the car, the acceleration decreases therefore in a graph the position values ​​are smaller for each time.

The linearity of the graph is maintained, but when calculating the slope it gives lower values.

In conclusion using Newton's second law and kinematics we can find the result of the error when placing the masses on the car is:

  • Acceleration decreases.
  • The plot of position vs. time squared is still linear, but the slope is less.

Learn more here: brainly.com/question/11298125

7 0
3 years ago
Read 2 more answers
D
ladessa [460]

Answer:

maibi.... D

Explanation:

I think is D

8 0
4 years ago
An ostrich can rub at speeds of up 72 km/h. How long will it take (in seconds) an ostrich to run 1.5 km at this top speed
mamaluj [8]

Answer:

A:75 seconds

Explanation:

1.5 km/72 km/h = 0 0208 h = 1.25 minutes = 75 seconds

7 0
3 years ago
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