It has a 10 electrons. Since it's atomic number is 11 it must have 11 protons. Also, given that it has a +1 charge, it has one less electron than protons since they have equal but opposite charges.
The number of protons is the mass number minus the atomic number = 23-11= 12 neutrons.
The force of the racket affects the ball's motion because it changes the momentum of the ball.
<h3>Impulse received by the ball</h3>
The impulse received by the ball through the racket affects the motion because it changes the momentum of the ball.
The ball which is initially at rest, will gain momentum after been hit with the racket.
J = ΔP = Ft
where;
- J is the impulse received by the ball
- ΔP is change in momentum of the ball
- F is the applied force
- t is the time of action
Thus, the force of the racket affects the ball's motion because it changes the momentum of the ball.
Learn more about impulse here: brainly.com/question/25700778
Answer:
Relativistic velocity is of the order of 1/10th of the velocity of light
Explanation:
We define relativistic speed (or velocity) as a speed that is a significant fraction of the speed of light: c = 3*10^8 m/s
Such that for these speeds, the special relativity theory starts to apply (the relativity effects starts to apply).
Usually, we define relativistic speeds as those that are of the order (or larger) of c/10, which is one-tenth of the speed of light.
Then the correct option is C:
Relativistic velocity is of the order of 1/10th of the velocity of light
Answer:
V=22.4m/s;T=2.29s
Explanation:
We will use two formulas in order to solve this problem. To determine the velocity at the bottom we can use potential and kinetic energy to solve for the velocity and use the uniformly accelerated displacement formula:
![mgh=\frac{1}{2}mv^{2}\\\\X= V_{0}t-\frac{gt^{2}}{2}](https://tex.z-dn.net/?f=mgh%3D%5Cfrac%7B1%7D%7B2%7Dmv%5E%7B2%7D%5C%5C%5C%5CX%3D%20V_%7B0%7Dt-%5Cfrac%7Bgt%5E%7B2%7D%7D%7B2%7D)
Solving for velocity using equation 1:
![mgh=\frac{1}{2}mv^{2} \\\\gh=\frac{v^{2}}{2}\\\\\sqrt{2gh}=v\\\\v=\sqrt{2*9.8\frac{m}{s^2}*25.6m}=22.4\frac{m}{s}](https://tex.z-dn.net/?f=mgh%3D%5Cfrac%7B1%7D%7B2%7Dmv%5E%7B2%7D%20%5C%5C%5C%5Cgh%3D%5Cfrac%7Bv%5E%7B2%7D%7D%7B2%7D%5C%5C%5C%5C%5Csqrt%7B2gh%7D%3Dv%5C%5C%5C%5Cv%3D%5Csqrt%7B2%2A9.8%5Cfrac%7Bm%7D%7Bs%5E2%7D%2A25.6m%7D%3D22.4%5Cfrac%7Bm%7D%7Bs%7D)
Solving for time in equation 2:
![-25.6m = 0\frac{m}{s}t-\frac{9.8\frac{m}{s^{2}}t^{2}}{2}\\\\-51.2m=-9.8\frac{m}{s^{2}}t^{2}\\\\t=\sqrt{\frac{51.2m}{9.8\frac{m}{s^{2}}}}=2.29s](https://tex.z-dn.net/?f=-25.6m%20%3D%200%5Cfrac%7Bm%7D%7Bs%7Dt-%5Cfrac%7B9.8%5Cfrac%7Bm%7D%7Bs%5E%7B2%7D%7Dt%5E%7B2%7D%7D%7B2%7D%5C%5C%5C%5C-51.2m%3D-9.8%5Cfrac%7Bm%7D%7Bs%5E%7B2%7D%7Dt%5E%7B2%7D%5C%5C%5C%5Ct%3D%5Csqrt%7B%5Cfrac%7B51.2m%7D%7B9.8%5Cfrac%7Bm%7D%7Bs%5E%7B2%7D%7D%7D%7D%3D2.29s)