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slavikrds [6]
3 years ago
6

Naproxen sodium, also known as Sodium 6-methoxy-α-methyl-2-napthaleneacetate, (C14H13NaO3), is an anti-inflammatory medication,

often used to treat rheumatic or musculoskeletal disorders. If each tablet contains 300 mg of naproxen sodium, and a typical adult dose is one tablet every eight hours. • Determine the molar mass of naproxen sodium. Show all steps to find the answer. • Calculate the number of moles of naproxen sodium in a single tablet. Show all steps to find the answer. • Calculate the number of moles of naproxen sodium that an adult would have taken if she took two doses of naproxen sodium in one day. Show all steps to find the answer.
Chemistry
1 answer:
swat323 years ago
8 0

1) molar mass of C₁₄H₁₃NaO₃ = 252 g/mole

2)  number of moles of naproxen sodium = 0.00119 moles

3) 0.00238 moles of naproxen in one day

Explanation:

1) Determine the molar mass of naproxen sodium.

We know that the molecular formula of naproxen sodium is C₁₄H₁₃NaO₃.

Now we can calculate the molar mass of naproxen sodium:

molar mass of C₁₄H₁₃NaO₃ = molar mass of C × 14 + molar mass of H × 13 + molar mass of Na × 1 + molar mass of O × 3

molar mass of C₁₄H₁₃NaO₃ = 12 × 14 + 1 × 13 + 23 × 1 + 16 × 3

molar mass of C₁₄H₁₃NaO₃ = 252 g/mole

2) Calculate the number of moles of naproxen sodium in a single tablet.

Knowing that one tablet contains 300 mg = 0.3 g of naproxen sodium, we use the following formula to find the number of moles:

number of moles = mass / molar weight

number of moles of naproxen sodium = 0.3 / 252

number of moles of naproxen sodium = 0.00119 moles

3) Calculate the number of moles of naproxen sodium that an adult would have taken if she took two doses of naproxen sodium in one day.

To find the number of moles taken by the adult in one day we follow the next reasoning:

if       1 tablet of naproxen contains 0.00119 moles of naproxen

then 2 tablets of naproxen contains X moles of naproxen

X = (2 × 0.00119) / 1 = 0.00238 moles of naproxen

Learn more about:

number of moles

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If 42.7 of 0.208 M hydrochloric acid are needed to completely neutralize a solution of calcium hydroxide, how many grams of calc
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Explanation:

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In a neutralization reaction, water is produced as a product, as well as a salt that we obtain after we exchange the cations: calcium bonds to chloride and hydrogen bonds to hydroxide (the latter is the formation of water). This means we also produce calcium chloride as a product. The overall reaction represents this as:

Ca(OH)_2(aq)+2 HCl (aq)\rightarrow CaCl_2 (aq)+2 H_2O (l)

Firslt of all, we wish to find the number of moles of HCl present. Having molarity and volume, this is done by applying the molarity formula. It states that molarity is equal to the rate between moles and volume:

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n_{Ca(OH)_2}=\frac{1}{2} n_{HCl}=\frac{1}{2}c_{HCl}V_{HCl}

Now that we have the expression for moles, we may also express moles of calcium hydroxide as the ratio between its mass and molar mass:

n_{Ca(OH)_2}=\frac{m_{Ca(OH)_2}}{M_{Ca(OH)_2}}

Using the last two equations, we see that:

\frac{1}{2}c_{HCl}V_{HCl}=\frac{m_{Ca(OH)_2}}{M_{Ca(OH)_2}}\\\therefore m_{Ca(OH)_2}=\frac{1}{2}c_{HCl}V_{HCl}M_{Ca(OH)_2}

Substitute the given data, as well as the molar mass of calcium hydroxide:

m_{Ca(OH)_2}=\frac{1}{2}\cdot0.208 M\cdot0.0427 L\cdot74.093 g/mol=0.329 g

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