Ask question

Ask question

All categories

3 years ago

13

As waves pass by a duck floating on a lake, the duck bobs up and down but remains in essentially one place. explain why the duck

is not carried along by the wave motion.

1 answer:

Rudiy273 years ago

3 0

The duck is not carried by the wave motion because <span>Waves move energy through a medium but don't transfer particles. So when the waves pass by a duck floating on a lake, the duck just bobs up and down, but remains in its place.</span>

You might be interested in

In the following figure, if AB ǁ CD, then find the measure of PCD and CPD.

mina [271]

Answer:

$CPD = 80$

$PCD = 44$

Explanation:

Given

$AB || CD$

$BAD = 56$

$CPA = 100$

See attachment

Required

Determine PCD and CPD

First, we need to calculate CPD

Since DPA is a straight line and CPA = 100;

We have that:

$CPA + CPD = 180$ --- angle on a straight theorem

Substitute 100 for CPA

$100 + CPD = 180$

Subtract 100 from both sides

$100-100 + CPD = 180-100$

$CPD = 80$

Next, we calculate PCD

We have that:

$DAB= ADC = 56$ --alternate angle

In triangle PCD

$PCD + CPD + PDC = 180$ --- angles in a triangle

Where

$PDC = ADC = 56$

So, we have:

$PCD +80 + 56 = 180$

$PCD +136 = 180$

Subtract 136 from both sides

$PCD = 180 - 136$

$PCD = 44$

6 0

3 years ago

A 5.00 kg mass is placed on top of a vertical spring, which compresses a distance of 3.13 cm. Calculate the force constant (in N

77julia77 [94]

Answer:

<h2>1567.09 N/m</h2>

Explanation:

Step one:

given data

mass m=5kg

compression x= 3.13cm to m= 0.0313m

<em>According to Hooke's law, provided the elastic limit of an elastic material is not exceeded the extension e is directly proportional to the applied force</em>

F=ke

where

k= spring constant in N/m

e= extension/compression in

Step two:

assume g= 9.81m/s^2

F=mg

F=5*9.81

F=49.05N

substitute in the expression F=ke

49.05=k*0.0313

k=49.05/0.0313

k=1567.09 N/m

<u>The force constant (in N/m) of the spring is 1567.09 N/m</u>

8 0

3 years ago

A box (m = 20 kg) is sliding on a horizontal surface. it is connected to a massless hook by a light string passing over a massle

Varvara68 [4.7K]

mass of the box = 20 kg

force of friction on the box due to surface

$F_s = \mu_s N$

$F_s = 0.80 * 20 * 9.8$

$F_s = 156.8 N$

similarly kinetic friction on it

$F_k = \mu_k N$

$F_k = 0.30* 20 * 9.8$

$F_k = 58.8 N$

now the weight of the suspended block will be

$W = mg = 15*9.8 = 147 N$

so here the weight of the suspended block is less than the limiting friction on it

So here we will say that friction will counter balance the weight of the suspended block and it will not move at all

So acceleration of the box will be zero

5 0

3 years ago

When you pick something up do you do work to it

vaieri [72.5K]

Answer:

Simple answer: Yes

Explanation:

Even if you touch an item with a stick you re still doing work to it, most of the time something sitting on a table not being disturbed is having work done to it. Everything has the force of gravity working on it to essentially keep the items from floating away so workis being done to it.

Work done can be something so small (e.g) a pencil sitting on a table) or as big as an earthquake or kicking a ball through a window and smashing the glass.

4 0

3 years ago

Why don't you notice your gravitational force on other objects?

mixas84 [53]

The answer is B tell me if I am wrong.

4 0

2 years ago

Read 2 more answers