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aksik [14]
3 years ago
8

Describe the flow of blood to the human body, including through each of the four chambers of the heart. Explain how the blood ch

anges as it moves through the various locations in the body.
Chemistry
2 answers:
patriot [66]3 years ago
7 0
This Is how it works blood<span> enters the </span>heart through<span> two large veins, the inferior and superior vena cava, emptying oxygen-poor </span>blood<span> from the </span>body<span> into the right atrium of the </span>heart<span>. As the atrium contracts, </span>blood flows<span> from your right atrium into your right ventricle </span>through<span> the open tricuspid valve.

Hope this helps <3</span>
xeze [42]3 years ago
3 0
Hey there,

The blood needs to flow at a great and constant speed. It can not flow very slow because that can be warning's of a heart attack because your blood is using alot of force and its trying to provide as much blood as possible to arrive at the heart in order for your body to live. This is why we should drink water because as we drink water, it helps our blood flow through out our body well and so that we ma not have any problem now and in the future.

~Jurgen 
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How many moles of potassium hydroxide are needed to completely neutralize 1.56 mol phosphoric acid?
frez [133]
3KOH + H₃PO₄ ----> K₃PO₄ + 3H₂O
3 moles 1 mole


3 moles KOH ------ 1 mole H₃PO₄
X moles KOH ------ 1,56 mol
X = 3×1,56
X = 4,68 moles of KOH

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7 0
3 years ago
What do you read the arrow in a chemical equation as meaning? One what does this sentence even mean it's worded oddly, and two I
Elanso [62]
The arrow means "yields" 
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8 0
3 years ago
Read 2 more answers
What volume (mL) of the partially neutralized stomach acid was neutralized by NaOH during the titration? (portion of 25.00 mL sa
almond37 [142]

The question is incomplete, here is the complete question:

What volume (mL) of the partially neutralized stomach acid having concentration 2 M was neutralized by 0.1 M NaOH during the titration? (portion of 25.00 mL NaOH sample was used; this was the HCl remaining after the antacid tablet did it's job)

<u>Answer:</u> The volume of HCl neutralized is 1.25 mL

<u>Explanation:</u>

To calculate the volume of acid, we use the equation given by neutralization reaction:

n_1M_1V_1=n_2M_2V_2

where,

n_1,M_1\text{ and }V_1 are the n-factor, molarity and volume of stomach acid which is HCl

n_2,M_2\text{ and }V_2 are the n-factor, molarity and volume of base which is NaOH.

We are given:

n_1=1\\M_1=2M\\V_1=?mL\\n_2=1\\M_2=0.1M\\V_2=25mL

Putting values in above equation, we get:

1\times 2\times V_1=1\times 0.1\times 25\\\\V_1=\frac{1\times 0.1\times 25}{1\times 2}=1.25mL

Hence, the volume of HCl neutralized is 1.25 mL

3 0
3 years ago
Timothy, a cashier, is given a twenty-dollar bill at his store. He is suspicious of the customer and wants to make sure the curr
Mice21 [21]
"<span>There is no change in the color of the bill's ink" is the one clue among the following choices given in the question that the currency is counterfeit. The correct option among all the options that are given in the question is the fourth option or the last option. I hope that the answer has come to your desired help.</span>
7 0
4 years ago
Read 2 more answers
What is the net ionic equation of the reaction of FeCl2 with NaOH? Express you answer as a chemical equation including phases.
Lilit [14]

Answer:

Fe²⁺(aq) + 2OH⁻(aq) → Fe(OH)₂(s)

Explanation:

To determine the reaction, we define the reactants:

FeCl₂, NaOH

We dissociate them:

FeCl₂(aq) → Fe²⁺(aq) + 2Cl⁻ (aq)

NaOH (aq) → Na⁺ (aq) + OH⁻(aq)

Salts from chloride are soluble, except for Ag⁺, Pb²⁺, Hg₂²⁺, Cu⁺

The OH⁻ and the Fe²⁺ bonds to make a precipitate.

So, the molecular complete equation is:

FeCl₂(aq) +  2NaOH(aq) →  Fe(OH)₂(s) ↓ + 2NaCl(aq)

When we dissociate the elements, we get the net ionic equation but as we produced an state's change, the compound stays the same.

We cancel the spectators ions (the ones, that are repeated)

Fe²⁺(aq) + 2Cl⁻ (aq) + 2Na⁺ (aq) + 2OH⁻(aq) → Fe(OH)₂(s) + 2Na⁺(aq) + 2Cl⁻(aq)

Fe²⁺(aq) + 2OH⁻(aq) → Fe(OH)₂(s)

5 0
3 years ago
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