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Goryan [66]
3 years ago
14

Planet with a density so low that it could float on water

Physics
1 answer:
Feliz [49]3 years ago
8 0

Answer:

(Saturn ) is the homogeneous mixture

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tester [92]
The temperature of the lithosphere is around 300<span>°C</span> - 500<span>°<span>C</span></span>


5 0
3 years ago
If you wanted the pitch of a horn to drop relative to an observer, which way would you move the horn, relative to where that obs
Vladimir [108]
We assume that horn releases sound of constant frequency. In order for observer to observe different frequency either horn or observer or both must move.

This happens due to Doppler effect. It states that when position of source of sound and observer relative to each other changes, the observed frequency also changes. If the source emits sound of constant frequency than observed frequency will be either higher or lower than original.

When distance between source and observer increases the observed frequency will be lower. This is because same number of sound waves must cover greater distance so they have greater wavelength.
When distance between source and observer decreases the observed frequency will be higher. This is because same number of sound waves must cover smaller distance so they have smaller wavelength. 

Wavelength and frequency are inversely proportional meaning when one increases the other drecreases.

From this explanation we can find answer for our question. <span>If we wanted the pitch of a horn to drop relative to an observer we need to move horn away from an observer.</span>
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A circular loop carrying a current of 1.6 A is oriented in a magnetic field of 0.30 T. The loop has an area of 0.14 m 2 and is m
konstantin123 [22]

Answer:

The torque on the loop is 2.4 \times 10^{-2} Nm

Explanation:

Given:

Current I = 1.6 A

Magnetic field B = 0.30 T

Area of loop A = 0.14 m^{2}

Angle between magnetic field and area vector \theta = 21°

Form the formula of  torque in case of magnetic field,

 г = MB \sin \theta

Where M = magnetic moment

  M = IA

 г = IAB \sin 21

 г = 1.6 \times 0.30 \times 0.14 \times 0.3583

 г =2.4 \times 10^{-2} Nm

Therefore, the torque on the loop is 2.4 \times 10^{-2} Nm

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