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wel
4 years ago
10

A 1200 kg car accelerates from 13m/s to 17m/s. find the change in momentum of the car?

Physics
1 answer:
lisabon 2012 [21]4 years ago
6 0

Answer:

4800

Explanation:

The change in velocity of the car is 17-13=4m/s. Since the change in momentum is the mass multiplied by the change in velocity, the answer is 4*1200=4800. Hope this helps!

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A lighter-than-air balloon and its load of passengers and ballast are floating stationary above the earth. ballast is weight (of
Natali5045456 [20]
Step 1: Find the upward acceleration. 
d = 107 m 
a = ??? 
vi = 0 
t = 14.4 sec 
d = vi * t + 1/2 at^2 
107 = 1/2 a * 14.4^2 
a = 214 / (14.4)^2 
a = 1.03 m/s^2 
Step 2: Find the Volume of the balloon and from that the mass. 

V = 4/3 * pi * r^3 
r = 6.52 m 
V = 4/3 x pi x 6.52^3
V= 1,161 m^3.
Density of air = m/V 1.29 = m/ 1161 
M = 1.29 x 1161
m = 1498 kg 
Step 3: The force keeping this in equilibrium = F = m* g 
F = 1498 * 9.81 = 14692 N 
Step 4: Find the mass needed to cause the upward acceleration. 
14692 = (1498 - x) * (9.81 + 1.03) 
14692 = (1498 - x) *  10.84 Divide both sides by 10.84 
1355.35 = 1022 - x 
1355.35 - 1022
x = 333.35 kg
7 0
3 years ago
The formula for electrical power is p = i v. Which is the equivalent equation solved for i? startfraction p over v endfraction =
Anettt [7]

The equivalent formula for p = iv is the startfraction p over v endfraction = i

In physics, power measures the rate of transfer of electrical energy through a circuit per unit of time. It is denoted by P and is measured using the SI unit of power (watts or 1 joule/second). Electrical energy is usually supplied by batteries and produced by generators.

There are three types of power, true, reactive, and apparent, which are related in trigonometric form. This is called the power triangle. A power triangle that relates apparent power to active and reactive power. Power is measured in watts. One watt equals one joule per second.

Learn more about the power in

brainly.com/question/24110214

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8 0
1 year ago
For a short period of time, the frictional driving force acting on the wheels of the 2.5-Mg van is N, where t is in seconds. If
KATRIN_1 [288]

Answer:

15.6m/s

Completed Question;

For a short period of time, the frictional driving force acting on the wheels of the 2.5-Mg van is N= 600t^2 , where t is in seconds. If the van has a speed of 20 km/h when t = 0, determine its speed when t = 5

Explanation:

Mass m = 2500kg

Speed v1 = 20km/h = 20/3.6 m/s = 5.556 m/s

To determine speed v2;

Using the principle of momentum and impulse;

mv1 + ∫₀⁵ F dt = mv2

8 0
3 years ago
A 100 N child slides down a frictionless inclined plane as shown in the figure below. Which one of the following statements is t
VladimirAG [237]

Answer:

Normal force may be less than weight, if there is some force with a component that acts opposite to the weight force. ... If the pulling force is horizontal, on a horizontal surface, then the normal force is equal to the weight. This is something your chould be able to see from a free-body diagram

Explanation:

4 0
3 years ago
Period vs string length
Galina-37 [17]
Trial 3 is the correct answer
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3 years ago
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