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asambeis [7]
3 years ago
10

To determine the trajectory of the movement of a material point in the xOz plane that is subjected simultaneously to oscillation

s x (t) = A * sin π(t + 1) and y (t) = A * sin (πt + π / 2).
Physics
1 answer:
nasty-shy [4]3 years ago
4 0

We are to show that the given parametric curve is a circle.

The trajectory of a circle with a radius r will satisfy the following relationship:

(x-x_c)^2 + (y-y_c)^2 = r^2

(with (x_c,y_c) being the center point)

We are given the x and y in a parametric form which can be further rewritten (using properties of sin/cos):

x(t) = A\sin \pi(t+1) = A\sin (\pi t + \pi) = -A\sin \pi t\\y(t) = A\sin (\pi t + \frac{\pi}{2}) = A\cos \pi t

Squaring and adding both gives:

x^2(t) + y^2(t) = A^2(-1)^2\sin^2 \pi t + A^2 \cos^2 \pi t = A^2\\\implies x^2 + y^2 = A^2

The last expression shows that the given parametric curve is a circle with the center (0,0) and radius A.


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130.7 N

Explanation:

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An electric heating element is connected to a 110 V circuit and a current of 3.2 A is flowing through the element. How much ener
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Power (rate of using energy) = (voltage) x (current)

Power of this heating element = (120 V) x (3.2 A) = 384 watts


The easy way:

     384 watts = 0.384 kilowatt

     (0.384 kilowatt) x (5 hours) = 1.92 kilowatt-hour


Another way:
     
                            384 watts = 384 joules per second .

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6 0
3 years ago
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Determina el trabajo realizado al desplazar un bloque 3 m sobre una superficie horizontal, si se desprecia la fricción y la fuer
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Answer: El trabajo realizado al desplazar el bloque es: 75 N.m

Datos:

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Distancia= d= 3 m

Explicación:

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Trabajo= Fuerza x Desplazamiento

Reemplazando los datos:

T= 25 N * 3 m

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A hot-air balloon is ascending at the rate of 12 m/s and is 80 m above the ground when a package is dropped over the side. (a) H
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Answer:

Explanation:

Given

balloon is ascending at the rate of u=12\ m/s

Balloon is at a height of s=80\ m

As the package is dropped from the balloon it must possess the same initial velocity as the balloon

using

v^2-u^2=2as  

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u=initial velocity

a=acceleration

s=displacement

v^2=12^2+2\times 9.8\times 80

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v=41.37\ m/s

time taken is  given by

v=u+at

substituting values

41.37=-12+9.8\times t

as we consider downward direction as positive

t=\frac{53.37}{9.8}

t=5.44\ s

therefore time taken to reach the bottom is t=5.44 s                                            

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