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asambeis [7]
3 years ago
10

To determine the trajectory of the movement of a material point in the xOz plane that is subjected simultaneously to oscillation

s x (t) = A * sin π(t + 1) and y (t) = A * sin (πt + π / 2).
Physics
1 answer:
nasty-shy [4]3 years ago
4 0

We are to show that the given parametric curve is a circle.

The trajectory of a circle with a radius r will satisfy the following relationship:

(x-x_c)^2 + (y-y_c)^2 = r^2

(with (x_c,y_c) being the center point)

We are given the x and y in a parametric form which can be further rewritten (using properties of sin/cos):

x(t) = A\sin \pi(t+1) = A\sin (\pi t + \pi) = -A\sin \pi t\\y(t) = A\sin (\pi t + \frac{\pi}{2}) = A\cos \pi t

Squaring and adding both gives:

x^2(t) + y^2(t) = A^2(-1)^2\sin^2 \pi t + A^2 \cos^2 \pi t = A^2\\\implies x^2 + y^2 = A^2

The last expression shows that the given parametric curve is a circle with the center (0,0) and radius A.


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sp2606 [1]

Answer:

1 ohm

Explanation:

First of all, the equivalent resistance for two resistors (r₁ and r₂) in parallel is given by:

1 / Eq = (1 / r₁) + (1 / r₂)

The equivalent resistance for resistance for two resistors (r₁ and r₂) in series is given by:

Eq = r₁ + r₂

Hence as we can see from the circuit diagram, 2Ω // 2Ω, and 2Ω // 2Ω, hence:

1/E₁ = 1/2 + 1/2

1/E₁ = 1

E₁ = 1Ω

1/E₂ = 1/2 + 1/2

1/E₂ = 1

E₂ = 1Ω

This then leads to E₁ being in series with E₂, hence the equivalent resistance (E₃) of E₁ and E₂ is:

E₃ = E₁ + E₂ = 1 + 1 = 2Ω

The equivalent resistance (Eq) across AB is the parallel combination of E₃ and the 2Ω resistor, therefore:

1/Eq = 1/E₃ + 1/2

1/Eq = 1/2 + 1/2

1/Eq = 1

Eq = 1Ω

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Explanation:

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A student with a mass of 62.0 kg walks up a flight of stairs with a height of 3.40 meters. If it takes him 7.00 seconds to get t
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Answer:

Power generate by generator = 265 W (Approx.)

Explanation:

Given:

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Power generate by generator

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