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PtichkaEL [24]
3 years ago
10

How many grams of sodium chloride are required to make a 1.0 L solution with a concentration of 3.5 M?

Chemistry
1 answer:
Alex777 [14]3 years ago
5 0

A 1 molar solution is the molecular weight in grams in 1 litre of water, so a 3.5 molar solution would be 58.44g multiplied by 3.5, which is 204.54g in 1L

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How does temp affect the phase of a substance
notka56 [123]

Answer:

state of matter

Explanation:

so take water for example, water has a melting point and a boiling point right? So if it's below 0 degrees, then it's in its solid phase. If the temperature is above 0 degrees, then the water starts to melt into its liquid phase. Then when the temperature is above 100 degrees, water starts to boil and become its gas phase. This is the same for all substances. The only difference is different substances have different melting and boiling points so the numbers will be different depending on your substance. hope this helped!

3 0
3 years ago
How many grams are in 1.76 x 10^23 atoms of iodine
Mariana [72]

Answer:

\boxed {\boxed {\sf About \ 37.1 \ grams \ of \ iodine }}

Explanation:

To convert from atoms to grams, you must first convert atoms to moles, then moles to grams.

1. Convert Atoms to Moles

To convert atoms to grams, Avogadro's number must be used.

6.022*10^{23}

This number tells us the number of particles (atoms, molecules, ions, etc.) in 1 mole. In this case, the particles are atoms of iodine.

\frac{6.022*10^{23} \ atoms \ I  }{1 \ mol \ I}

Multiply the given number of atoms by Avogadro's number.

1.76*10^{23} \ atoms \ I*\frac{6.022*10^{23} \ atoms \ I  }{1 \ mol \ I}

Flip the fraction so the atoms of iodine will cancel out.

1.76*10^{23} \ atoms \ I*\frac{  1 \ mol \ I}{6.022*10^{23} \ atoms \ I}

1.76*10^{23}* \frac{1 \ mol \ I}{6.022*10^{23} }

Multiply so the problem condenses into 1 fraction.

\frac{1.76*10^{23} \ mol \ I}{6.022*10^{23} }

0.2922617071 \ mol \ I

2. Convert Moles to Grams

Now we must use the molar mass of iodine, which is found on the Periodic Table.

  • Iodine Molar Mass: 126.9045 g/mol

Use this mass as a fraction.

\frac{ 126.9045 \ g\ I }{ 1 \ mol \ I}

Multiply this fraction by the number of moles found above.

0.2922617071 \ mol \ I*\frac{ 126.9045 \ g\ I }{ 1 \ mol \ I}

Multiply. The moles of iodine will cancel.

0.2922617071 *\frac{ 126.9045 \ g\ I }{ 1 }

The 1 as a denominator is insignificant.

0.2922617071 *{ 126.9045 \ g\ I }

37.08932581 \ g \ I

3. Round

The original measurement of 1.76*10^23 has 3 significant figures (1, 7, and 6). Therefore we must round our answer to 3 sig figs. For this answer, that is the tenths place.

37.08932581 \ g \ I

The 8 in the hundredth place tells us to round the 0 up to a 1.

\approx 37.1\ g \ I

There is about <u>37.1 grams of iodine </u>in 1.76*10^23 atoms.

5 0
3 years ago
Can some body plz help correct me or correct the true or false answers I did wrong. I’m not sure there right :(
3241004551 [841]

4 3 and 5 are wrong:)

4 is true and 5 is false

4. insulators are really thick materials that keep electrons within their space.

For example, a charger the rubber is the insulators and the electrons are flowing inside of the charger so you don't get shocked.

5. without the force of attraction, there are no atoms:)

for number 3, its a trick question

Hope this helped!

(learned these this year so I didn't forget them:)

8 0
3 years ago
Pls help me with my homework
mafiozo [28]

Explanation:

Charles's law is one of the gas laws which explains that at constant pressure, the temperature and volume of a gas are directly proportional to each other. According to kinetic theory, as temperature rises the kinetic energy of gas also increases proportionally

8 0
3 years ago
Why is DNA important?
Nitella [24]

Answer:

DNA is pivotal to our growth, reproduction, and health. It contains the instructions necessary for your cells to produce proteins that affect many different processes and functions in your body. Because DNA is so important, damage or mutations can sometimes contribute to the development of disease

<h2>hσpє ít αgαín hєlpѕ uh</h2><h3>plѕ mαrk mє αѕ вrαínlíєѕt</h3>
3 0
3 years ago
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