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katrin2010 [14]
2 years ago
13

Calculating pH

Chemistry
1 answer:
saveliy_v [14]2 years ago
3 0

Answer:

The answer to your question is given below

Explanation:

1. Data obtained from the question include:

Hydrogen ion concentration, [H+] = 1x10^-9M

pH =..?

pH = - log [H+]

pH = - log 1x10^-9

pH = 9

2. Data obtained from the question include:

pOH = 3

pH =.?

Recall:

pH + pOH = 14

pH + 3 = 14

Collect like terms

pH = 14 - 3

pH = 11

3. Data obtained from the question include:

Hydroxide ion concentration, [OH-] = 1x10^-2M

pH =..?

First, we shall determine the pOH. This is illustrated below

pOH = - Log [OH-]

pOH = - Log 1x10^-2

pOH = 2

Finally, we can obtain the pH as follow:

pH + pOH = 14

pOH = 2

pH + 2 = 14

Collect like terms

pH = 14 - 2

pH = 12

4. Data obtained from the question include:

pOH = 7

pH =.?

Recall:

pH + pOH = 14

pH + 7 = 14

Collect like terms

pH = 14 - 7

pH = 7

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Explanation:

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As evident from the graph, electron kinetic energy remains at zero as long as the frequency of incident light is less than v₀.

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And the slope of the line segment is Energy of ejected electrons/frequency of incident light, E/v₀, which adequately matches the Planck's constant, h = 6.63 × 10⁻³⁴ J.s

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