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pochemuha
4 years ago
10

What are 3 phases of matter how do particles move

Chemistry
2 answers:
DedPeter [7]4 years ago
7 0

Answer:

solid liquid gas

Explanation:

GalinKa [24]4 years ago
6 0
Gas moves fast and freely liquid slower and closer and solid is super close and super slow
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Which acid was most likely used for the titration graph below.
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What happens when you break earphones into smaller pieces
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Explanation:

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3 years ago
A 25.00-mL sample of propionic acid, HC3H5O2, of unknown concentration was titrated with 0.141 M KOH. The equivalence point was
Nastasia [14]

Answer:

Concentration of hydroxide-ion at equivalence point = 8.3\times 10^{-6}M

Explanation:

HC_{3}H_{5}O_{2}+KOH\rightarrow C_{3}H_{5}O_{2}^{-}K^{+}+H_{2}O

1 mol of HC_{3}H_{5}O_{2} reacts with 1 mol of KOH to produce 1 mol of C_{3}H_{5}O_{2}^{-}

At equivalence point, all HC_{3}H_{5}O_{2} gets converted to C_{3}H_{5}O_{2}^{-}.

Moles of C_{3}H_{5}O_{2}^{-} produced at equivalence point is equal to moles of KOH added to reach equivalence point.

So, moles of C_{3}H_{5}O_{2}^{-} produced = \frac{43.76\times 0.141}{1000}moles=0.00617moles

Total volume of solution at equivalence point = (25.00+43.76) mL = 68.76 mL

Concentration of C_{3}H_{5}O_{2}^{-} at equivalence point = \frac{0.00617\times 1000}{68.76}M=0.0897M

OH^{-} produced at equivalence point is due to hydrolysis of C_{3}H_{5}O_{2}^{-}. We have to construct an ICE table to calculate concentration of OH^{-} at equivalence point.

C_{3}H_{5}O_{}^{-}+H_{2}O\rightleftharpoons HC_{3}H_{5}O_{2}+OH^{-}

I:0.0897                               0                    0

C: -x                                     +x                   +x

E: 0.0897-x                          x                      x

\frac{[HC_{3}H_{5}O_{2}][OH^{-}]}{[C_{3}H_{5}O_{2}^{-}]}=K_{b}(C_{3}H_{5}O_{2}^{-})=\frac{10^{-14}}{K_{a}(HC_{3}H_{5}O_{2})}

species inside third bracket represent equilibrium concentrations

So, \frac{x^{2}}{0.0897-x}=7.69\times 10^{-10}

or, x^{2}+(7.69\times 10^{-10}\times x)-(6.90\times 10^{-11})=0

So, x=\frac{-(7.69\times 10^{-10})+\sqrt{(7.69\times 10^{-10})^{2}+(4\times 6.90\times 10^{-11})}}{2}M = 8.3\times 10^{-6}M

So, concentration of hydroxide-ion at equivalence point = x M =  8.3\times 10^{-6}M

8 0
3 years ago
How did energy from inside of the earth cause a boat to end up on top of a building
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The energy built up in the earth could have caused a tectonic plates movement. The movement could have made a tsunami and moved the boat. The impact could have caused the boat to move up to the top of a building.

8 0
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