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Pavlova-9 [17]
3 years ago
14

a motorboat starting from rest on a lake accelerates in a straight line at a constact rate of 3m/s square for 8sec.how far does

the boat travel during this time?
Physics
1 answer:
zimovet [89]3 years ago
4 0
So check it out you can just use the old formula
v =  \frac{d}{t}
instead of deviding distance and time multiply velocity and time
so the formula would be
v \times t = d
3ms \times 8sec = 24m
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A 873-kg (1930-lb) dragster, starting from rest completes a 401.4-m (0.2509-mile) run in 4.945 s. If the car had a constant acce
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To solve this problem it is necessary to apply the kinematic equations of motion.

By definition we know that the position of a body is given by

x=x_0+v_0t+at^2

Where

x_0 = Initial position

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a = Acceleration

t= time

And the velocity can be expressed as,

v_f = v_0 + at

Where,

v_f = Final velocity

For our case we have that there is neither initial position nor initial velocity, then

x= at^2

With our values we have x = 401.4m, t=4.945s, rearranging to find a,

a=\frac{x}{t^2}

a = \frac{ 401.4}{4.945^2}

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