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-Dominant- [34]
3 years ago
13

What is the potential energy of a 50 newton object resting on the edge of a cliff 30 meters high?

Physics
1 answer:
mojhsa [17]3 years ago
3 0
The potential energy of the object is going to be gravitational: PE=mgh. Assuming we're talking about the gravitational potential energy relative to the bottom of the cliff, the object's height is 30 m. g is 9.8 m/s^2. We don't know its mass. You could technically use the equation F=mg to find the mass, where F=40 and g=9.8, but that's unnecessary. You can just substitute F into PE=mgh to get PE=Fh. Substitute the given values to get PE=40*30=120 J.
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The intensity at distance from a spherically symmetric sound source is 100 W/m2. What is the intensity at five times this distan
ss7ja [257]

To solve this problem it is necessary to apply the concepts related to intensity as a function of power and area.

Intensity is defined to be the power per unit area carried by a wave. Power is the rate at which energy is transferred by the wave. In equation form, intensity I is

I = \frac{P}{A}

The area of a sphere is given by

A = 4\pi r^2

So replacing we have to

I = \frac{P}{4\pi r^2}

Since the question tells us to find the proportion when

r_1 = 5r_2 \rightarrow \frac{r_2}{r_1} = \frac{1}{5}

So considering the two intensities we have to

I_1 = \frac{P_1}{4\pi r_1^2}

I_2 = \frac{P_2}{4\pi r_2^2}

The ratio between the two intensities would be

\frac{I_1}{I_2} = \frac{ \frac{P_1}{4\pi r_1^2}}{\frac{P_2}{4\pi r_2^2}}

The power does not change therefore it remains constant, which allows summarizing the expression to

\frac{I_1}{I_2}=(\frac{r_2}{r_1})^2

Re-arrange to find I_2

I_2 = I_1 (\frac{r_1}{r_2})^2

I_2 = 100*(\frac{1}{5})^2

I_2 = 4W/m^2

Therefore the intensity at five times this distance from the source is 4W/m^2

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</span>Potential Energy :
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</span>
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