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Crazy boy [7]
3 years ago
12

If you have 6 moles of reactant A and excess of B and C, how much product E would be formed?

Chemistry
1 answer:
riadik2000 [5.3K]3 years ago
3 0

To be able to solve this problem, we must be given the balanced chemical equation:

3A + 5B + 1C ---> 2D + 1E

 

Our reactant A is called the limiting reactant because it is limited in amount which is only 6 moles. So we based our calculation on that reactant alone.

From stoichiometry, we have 1 mole of E for every 3 moles of A, therefore:

 

moles E = 6 moles A * (1 mole E / 3 moles A)

moles E = 2 moles

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From the question given above, the following data were obtained:

Volume of stock solution (V₁) = 55 mL

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