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Tatiana [17]
4 years ago
14

What is the angular diameter of planet Jupiter as seen from Earth? We know that the diameter of Jupiter is and the minimum dista

nce from Earth to Jupiter is . 25 arcsec 50 arcsec 60 arcsec 0.5 arcsec
Physics
1 answer:
N76 [4]4 years ago
3 0

Answer:

50 arcsec.

Explanation:

Diameter of the Jupiter is 139822 km.

Minimum distance of the Jupiter from the earth is,

S=588\times 10^{6}km

Now angular diameter of the Jupiter from the Earth can be calculate as,

\theta=\frac{D}{S}

Here, D is the diameter, and S is the minimum distance from the observing planet.

Now,

\theta=\frac{139822 km}{588\times 10^{6}km}\\\theta=237.792517\times 10^{-6} arcradian

We know that,

1radian= \frac{180\times 60\times 60}{\pi } arcsec

Therefore,

\theta=237.792517\times 10^{-6}(\frac{180\times 60\times 60}{\pi } arcsec)\\\theta=49.07arcsec

Therefore, the angular diameter of planet Jupiter is 49.07 arcsec which is quite close to the 50 arcsec which is given in options.

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