Answer:
450g of coke (C)
Explanation:
Step 1:
The balanced equation for the reaction is given below:
3C(s) + 2SO2(g) —> CS2(s) + 2CO2(g)
Step 2:
Determination of the mass of C that reacted and the mass of CS2 produced from the balanced equation.
This is illustrated below:
Molar Mass of C = 12g/mol
Mass of C from the balanced equation = 3 x 12 = 36g
Molar Mass of CS2 = 12 + (32x2) = 12 + 64 = 76g/mol.
From the balanced equation above, 36g of C reacted to produce 76g of CS2.
Step 3:
Determination of the mass of C required to produce 950g of CS2. This is illustrated below:
From the balanced equation above, 36g of C reacted to produce 76g of CS2.
Therefore, Xg of C will react to produce 950g of CS2 i.e
Xg of C = (36 x 950)/76
Xg of C = 450g
From the calculations made above, 450g of coke (C) is needed to produce 950g of CS2.
The new temperature : 11.56 °C
<h3>Further explanation </h3>
Boyle's law and Gay Lussac's law

P1 = initial gas pressure (N/m² or Pa)
V1 = initial gas volume (m³)
P2 = final gas pressure
V2 = final gas volume
T1 = initial gas temperature (K)
T2 = final gas temperature
V₁=4.39 L
T₁=44+273=317 K
P₁ = 729 torr = 0,959211 atm
V₂=3.78 L
P₂= 1 atm

Answer:
2KOH(aq) + NiSO₂(aq) → K₂SO₄(aq) + NiOH₂(s)
Explanation:
This reaction is an example of a <em>double-replacement reaction </em>where the cations of two compounds exchange with its anions. In the reaction:
KOH(aq) + NiSO₄(aq)
There are produced K₂SO₄ and NiOH₂ salts (The last one is insoluble, its state is (s) but K₂SO₄ is very soluble, its state is (aq). The unbalanced reaction is:
KOH(aq) + NiSO₄(aq) → K₂SO₄(aq) + NiOH₂(s)
To balance the potassiums:
<h3>
2KOH(aq) + NiSO₂(aq) → K₂SO₄(aq) + NiOH₂(s)</h3>
And now, the reaction is balanced
By the following above the compounds would contain a total of seven carbon atom: c. 2-heptene
hept is 7, heptene contain seven carbon atom.
hope this help
Answer:
96.11 g/mol
General Formulas and Concepts:
<u>Chemistry - Atomic Structure</u>
Explanation:
<u>Step 1: Define</u>
(NH₄)₂CO₃
<u>Step 2: Identify</u>
Molar Mass of N - 14.01 g/mol
Molar Mass of H - 1.01 g/mol
Molar Mass of C - 12.01 g/mol
Molar Mass of O - 16.00 g/mol
<u>Step 3: Find</u>
Molar mass of (NH₄)₂CO₃ - 2(14.01) + 8(1.01) + 12.01 + 3(16.00) = 96.11 g/mol