Explanation:
It is given that,
length of steel wire, l = 0.75 m
Mass of the wire, m = 12 g = 0.012 kg
Fundamental frequency, f = 120 Hz
We need to find the mass of the anvil (m'). The fundamental frequency is given by :

v is the speed of the mass
Speed is given by :

is the mass per unit length,

T is the tension in the wire,



T = 518.4 N
Tension in the wire, T = m' g


m' = 52.89 kg
So, the mass of the anvil is 52.89 kg. Hence, this is the required solution.
Answer:
T'=92.70°C
Explanation:
To find the temperature of the gas you use the equation for ideal gases:

V: volume = 3000cm^3 = 3L
P: pressure = 1250mmHg; 1 mmHg = 0.001315 atm
n: number of moles
R: ideal gas constant = 0.082 atm.L/mol.K
T: temperature = 27°C = 300.15K
For the given values you firs calculate the number n of moles:
![n=\frac{PV}{RT}=\frac{(1520[0.001315atm])(3L)}{(0.082\frac{atm.L}{mol.K})(300.15K)}=0.200moles](https://tex.z-dn.net/?f=n%3D%5Cfrac%7BPV%7D%7BRT%7D%3D%5Cfrac%7B%281520%5B0.001315atm%5D%29%283L%29%7D%7B%280.082%5Cfrac%7Batm.L%7D%7Bmol.K%7D%29%28300.15K%29%7D%3D0.200moles)
this values of moles must conserve when the other parameter change. Hence, you have V'=2L and P'=3atm. The new temperature is given by:

hence, T'=92.70°C
Explanation:
If a metal rod of length L moves with velocity v is moving perpendicular to its length, in a magnetic field B, the induced emf is given by :

The electric field in the conductor is given by :

It is clear that the electric field is independent of the length of the rod. If the length of the rod is doubled, the electric field in the rod remains the same.
Answer:
d. According to the previous theorem:
(kh^2)/2-mgh-(m(2v)^2)/2=0,
126h^2-2.577h-8.236=0,
h=0.266 m.
Explanation: