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lora16 [44]
3 years ago
6

At a location, rainwater runs off the face of a cliff that is 15 meters high. How is the face of the cliff likely to change over

time?
Weathering by water would cut its middle deeper than the top.
Weathering by water would cut its top deeper than the middle.
The top would slope gently due to deposition of sediments.
Colored mineral streaks would be formed due to erosion.
Physics
1 answer:
stiv31 [10]3 years ago
5 0
Weathering by water would cut its top deeper than the middle
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An object moves 2.5 m. This is an example of a _______.
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The correct answer is A. Distance

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One container has 100 mL of water and a second container has 1000 mL of water. If the temperature in both containers is 22 C (71
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A neighbor's child wants to go to a neighborhood carnival to experience the wild rides. The neighbor is worried about safety as
seraphim [82]

Answer:

No, the ride is not safe

Explanation:

From the diagram attached, it is seen that

\sum f_{y} = 0

\tau cos \theta - W = 0................(1)

\sum f_{x} = 0

-ma + \tau sin \theta = 0.......(2)

a = w^{2} r

From the diagram, r = Lsin \theta

a = w^{2} L sin \theta

w = \frac{2\pi }{T}

a = \frac{4\pi ^{2}L sin \theta }{T^{2} }............(3)

Put (3) into (2)

\tau sin \theta = \frac{4\pi ^{2}m L sin \theta }{T^{2} }

\tau  = \frac{4\pi ^{2}m L  }{T^{2} }

w = weight of chair + weight of child = 50 + 10 = 60 lb

g = 32 ft/s²

m = w/g = 60/32 = 1.875

L = 30 ft

T = 3 secs

\tau  = \frac{4\pi ^{2}*1.875*30  }{0.3^{2} }

\tau = 246.74 lbs

since 246.74 lbs > 200 lbs, it is not safe because the stationary chair will creak

6 0
3 years ago
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Does anyone know this or done it? It’s for life skills and about MyPlate:)
vivado [14]
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A power plant produces 1000 MW to supply a city 40 km away. Current flows from the power plant on a single wire of resistance 0.
nikitadnepr [17]

Answer:

Current = 8696 A

Fraction of power lost = \dfrac{80}{529} = 0.151

Explanation:

Electric power is given by

P=IV

where I is the current and V is the voltage.

I=\dfrac{P}{V}

Using values from the question,

I=\dfrac{1000\times10^6 \text{ W}}{115\times10^3\text{ V}} = 8696 \text{ A}

The power loss is given by

P_\text{loss} = I^2R

where R is the resistance of the wire. From the question, the wire has a resistance of 0.050\Omega per km. Since resistance is proportional to length, the resistance of the wire is

R = 0.050\times40 = 2\Omega

Hence,

P_\text{loss} = \left(\dfrac{200000}{23}\right)^2\times2

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3 0
3 years ago
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