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3 years ago

The resulting net force of an object is represented below.

Physics

2 answers:

yKpoI14uk [10]3 years ago

4 0

Answer:

← 63 N and → 73 N

Explanation: i think plz tell me if im wrong

nataly862011 [7]3 years ago

4 0

Answer:

← 63 N and → 73 N

Explanation:

I if anyone is part of 4376 like this now

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Electric current in electric bulb is 20 mA, what is the charge flowing through the filament in 4 sec

anzhelika [568]

Answer:

The charge flowing through the filament is 0.08C

Explanation:

$I=20mA = 0.02A\\t= 4s\\$

Plug your given values into the charge and current formula:

$I=\frac{Q}{t} \\Q=I*t\\Q= (0.02A)(4s)\\Q= 0.08C$

6 0

3 years ago

Suppose you are an astronaut on a spacewalk, far from any source of gravity. You find yourself floating alongside your spacecraf

erik [133]

Answer:

c. Throw the items away from the spaceship.

Explanation:

By the Principle of action and reaction yu can get back to your spacecraft throwing the items away from the spaceship.

7 0

4 years ago

Read 2 more answers

20. There are two electrical devices, one is electrical kettle of 2KW-200V and

RUDIKE [14]

Electrical kettle:

P = 2 KW = 2000 W

U = 200 V

⇒ I = P/U = 2000 / 200 = 10 A

We apply the Law of Ohm:

R = U / I = 200V / 10A = 20 Ω

=======

Electrical heater:

P = 1 KW = 1000 W

U = 240 V

⇒ I = P/U = 1000 / 240 = 4,16 A

We apply the Law of Ohm:

R = U / I = 240V / 4,16A = 57,69 Ω

Answer:

The device with the highest resistance is the electric heater.

6 0

4 years ago

Which of the following values can you find by calculating the slope of a graph of velocity versus time? A. Acceleration B. Veloc

Lady_Fox [76]

A. acceleration.

On a Velocity vs Time graph the slope will always be equal to the acceleration. I.e. if the slope is negative, so is the acceleration and vice versa.

5 0

4 years ago

Read 2 more answers

Consider a double-slit with a distance between the slits of 0.04 mm and slit width of 0.01 mm. Suppose the screen is a distance

scZoUnD [109]

Answer:

The distance between the places where the intensity is zero due to the double slit effect is 15 mm.

Explanation:

Given that,

Distance between the slits = 0.04 mm

Width = 0.01 mm

Distance between the slits and screen = 1 m

Wavelength = 600 nm

We need to calculate the distance between the places where the intensity is zero due to the double slit effect

For constructive fringe

First minima from center

$x_{1}=\dfrac{\lambda D}{2d}$

Second minima from center

$x_{2}=\dfrac{3\lambda D}{2d}$

The distance between the places where the intensity is zero due to the double slit effect

$\Delta x_{d}=x_{2}-x_{1}$

$\Delta x_{d}=\dfrac{3\lambda D}{2d}-\dfrac{\lambda D}{2d}$

$\Delta x_{d}=\dfrac{\lambda D}{d}$

Put the value into the formula

$\Delta x_{d}=\dfrac{600\times10^{-9}\times1}{0.04\times10^{-3}}$

$\Delta x_{d}=0.015 =15\times10^{-3}\ m$

$\Delta x_{d}=15\ mm$

Hence, The distance between the places where the intensity is zero due to the double slit effect is 15 mm.

8 0

3 years ago