Answer:
75.84%
Explanation:
We were given Speed of the sports car, v as 80 mph , we can convert to m/s for unit consistency.
v=80mph= 35.76 m/s
The radius of curvature is given as , r = 540 m
✓ the normal weight can be denoted as Wn
✓ the apparent weight of the person can be denoted as Wa
Wn= normal weight= mg
Wa=apparent weight = (mg - mv^2/r)
g= acceleration due to gravity= 9.8m/s^2
The apparent weightand normal weight has a ratio of
Mn/Ma= [mg - mv^2/r]/mg ........eqn(1)
If we simplify eqn(1) we have
Mn/Ma=[g - vr^2/g].............eqn(2)
Then substitute the given values
Mn/Ma=9.8 - [(35.76^2)/540]/ 9.8
=0.758×100%
Mn/Ma=75.84%
Hence, the required fraction is 75.84%
