As per Definition of acceleration we know that rate of change in velocity of object is known as acceleration
so when we apply push on an object that push or applied force will change the velocity of object always
so correct answer must be
a.) changed the velocity
The two possible angles obtained by using the qudratic equation are;
θ = 15.10° and θ2 = 73.51°
Given, speed of water = = 50ft/s
For the motion along x direction, time period can be calculated as follows:
35 = (50 × cosθ) t
t = 0.64 / cosθ
For the motion in y direction, an equation can be obtained as follows:
θ)
Plugging in the values we get:
θ)
-20 = -32tanθ - 10.304θ
Upon solving the above quadratic equation, we get,
tanθ = 0.27 , -3.38
Therefore,
tanθ = 0.27
θ = 15.10°
and, tanθ = -3.38
θ = 73.51
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To solve this problem it is necessary to apply the equations related to the conservation of momentum. Mathematically this can be expressed as
Where,
= Mass of each object
= Initial velocity of each object
= Final Velocity
Since the receiver's body is static for the initial velocity we have that the equation would become
Therefore the velocity right after catching the ball is 0.0975m/s
Answer:
Option C
100 J
Explanation:
Kinetic energy, KE is given by
where m is the mass and v is the velocity
Substituting 50 Kg for mass, m and 2 m/s for velocity v then we obtain
Therefore, the child's kinetic energy is equivalent to 100 J