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nirvana33 [79]
3 years ago
9

Which best explains why changes to the atomic theory were necessary? (2 points)

Chemistry
2 answers:
RSB [31]3 years ago
5 0
It would be the first two because 3 and 4 are irrelevant to the atomic theory :)
STALIN [3.7K]3 years ago
3 0
The answer is A because every ones theory cant be the same

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How many grams of H2 are needed to react with 47 grams of N2 to produce 200 grams of NH3?
Oduvanchick [21]
I think it’s law conservation of mass.

So 200g(NH3)-47g(N2)=153g(H2)

H2+N2—->NH3
5 0
4 years ago
Superheated steam at 20 bar and 450oC flows at a rate of 200 kg/min to an adiabatic turbine, where it expands to 10 bar. The tur
sergejj [24]

Explanation:

The given data is as follows.

Pressure of steam at inlet of turbine, P_{1} = 20 bar

Temperature at inlet of turbine, T = 450^{o}C

Pressure at outlet of turbine, P_{2} = 10 bar  

Mass flow rate of steam, m = 200 kg/min

Work produced by the turbine, W_{s} = 1500 kW

Steam is heated at constant pressure to its initial temperature, i.e., temperature at outlet of heat exchanger, T_{3} = 450^{o}C.

(1)   For an adiabatic turbine, the energy balance is  as follows.

           -W_{s} = m({H}_{2} - {H}_{1})

where W_{s} = work done by the turbine

                      m = mass flow rate of steam

H_{1} and H_{2} are the specific enthalpy of steam at inlet and outlet conditions of turbine.

Obtain the specific enthalpy of steam from Properties of Superheated Steam table

At 20 bar and 450^{o}C, H_{1} = 3358 kJ/kg

           H_{2} = H_{1} - \frac{W_{s}}{m}

      H_{2} = 3358 kJ/kg - \frac{1500kJ/s \times 60 s/min}{200 kg/min}

           H_{2} = 2908 kJ/kg

For P = 10 bar, H =2875 kJ/kg for T= 200^{0}C and H = 2975 kJ/kg for T=250^{o}C. Interpolate the values.

The temperature corresponding to P = 10 bar and H_{2} = 2908 kJ/kg is T = 216.5^{o}C

Therefore, the outlet temperature is T_{2} = 216.5^{o}C.

(2)     Energy balance on the heater is  as follows.

         Q = \Delta H = m(H_{3} - H_{2})

where,        Q = heat input required by the steam

                \Delta H = specific enthalpy change

           H_{3} = specific enthalpy of steam at the outlet conditions of heat exchanger

At P = 10 bar and T_{3} = 450^{o}C,  H_{3} = 3371 kJ/kg.

          Q = \frac{200 kg/min}{60 s/min} \times (3371 - 2908)kJ/kg

[/tex]

          Q = 1543.33 kJ/s

or,    Q = 1543.33 kW

Therefore, the heat input required is Q = 1543.33 kW.

8 0
4 years ago
HELPP!!! Find the mass of a rock with a density of 1.36 g/ml, if the rock is placed in a graduated cylinder and the water rises
bonufazy [111]

Answer:

<h2>The answer is 6.12 g</h2>

Explanation:

The mass of a substance when given the density and volume can be found by using the formula

<h3>mass = Density × volume</h3>

From the question

density of rock = 1.36 g/mL

volume = final volume of water - initial volume of water

volume = 21.3 - 16.8 = 4.5 mL

The mass of the rock is

mass = 1.36 × 4.5

We have the final answer as

<h3>6.12 g</h3>

Hope this helps you

7 0
3 years ago
Why does the temperature of different layers of the atmosphere vary
scoundrel [369]
It has different reasons. the temperature difference is basically the main reason why the earth atmosphere has layers.
Theoretically the temperature varies because of the different molecules and atoms. for instance the first layer known as troposphere has the greenhouse effect of CO2,CH4, etc. and is covered with a layer of O3...
7 0
3 years ago
Make the following conversion 240 hm = __ m
Juli2301 [7.4K]
240 Hm = 24000 Metres :)
6 0
4 years ago
Read 2 more answers
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