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Ivanshal [37]
3 years ago
6

Your lab partner turns to get a pencil, and accidentally knocks over and breaks a test tube full of sulfuric acid. What should y

ou do first? A) Pour water on the spill to dilute the acid. B) Immediately find a chemical to neutralize the acid. C) Place paper towels over the spill to soak up the acid quickly. D) Safely get away from the spill, and notify your instructor immediately.
Chemistry
2 answers:
Anni [7]3 years ago
5 0
Hey smarty!

Your answer would be, <span>D) Safely get away from the spill, and notify your instructor immediately. Better to be safe than sorry!

Hope this helps!

-Much love, Makayla
</span><span />
Troyanec [42]3 years ago
4 0
The answer to your question is D. hope this helps
-dabs-

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If 60.0 ml of a 1.5 m hcl solution is put into a flask and diluted with water to make 2.0 l of solution
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Answer:

The molarity of the diluted HCl solution: <u>M₂ = 0.045 M</u>  

Explanation:

To find- the molarity of the diluted HCl solution (M₂)

Given- <u>For original HCl solution</u>-

Molarity: M₁ = 1.5 M, Volume: V₁ = 60.0 ml = 0.06 L          (∵ 1L = 1000 mL)

Then this original solution is diluted to a volume of 2 L

Thus <u>for the diluted HCl solution</u>-  

The Volume of the diluted HCl solution: V₂ = 2 L

<u>So the Molarity of the diluted HCl solution (M₂) can be calculated by the </u><u><em>dilution equation:</em></u>

M_{1}\times V_{1} = M_{2}\times V_{2}

\Rightarrow M_{2} = \frac{M_{1}\times V_{1}}{V_{2}}

\Rightarrow M_{2} = \frac{1.5 M\times 0.06 L}{2 L} = 0.045 M

<u>Therefore, the molarity of the diluted HCl solution: M₂ = 0.045 M</u>

7 0
3 years ago
Given the values for C (2.5) and O (3.5), calculate the electronegativity difference in a carbon monoxide bond, CO
34kurt

Answer:

ΔEN CO   = 1.0

Explanation:

To calculate the electronegativity difference, we have to substract the element which has the highest EN to the other, that has a low value.

For this case EN from O - EN from C

Electronegativity is a property of the periodic table that increases diagonally, where Fr and Rb are the elements of less EN while F is the most electronegative element, with a value of 4. This is because F is an element with a high ionization energy and a negative electronic affinity.

ΔEN CO  = 3.5 - 2.5 = 1.0

Electronegativity (EN) describes the ability of an atom to compete for

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