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3 years ago

13

What do radio waves and microwaves have in Common?

1 answer:

DerKrebs [107]3 years ago

3 0

What do radio waves and microwaves have in Common?

<u>A) Both are at the ideological the spectrum that has the lowest frequency. </u>

B) Both are at the spectrum that has the shortest wavelengths.

C) Both have higher frequencies than visible light.

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How many meters are in a gigameter?

gladu [14]

Answer:

1 gigameter = 1e+9 meter

7 0

4 years ago

what is a point of view of an object used to determine another obejects motion i nedd help asap plsss

Igoryamba

A believe that’s called a reference point.

9 0

4 years ago

An electron initially has a speed 16 km/s along the x-direction and enters an electric field of strength 27 mV/m that points in

weqwewe [10]

Answer:

a) $t=1.4\times 10^{-5}\ s$

b)S= 46.4 cm

Explanation:

Given that

Velocity = 16 Km/s

V= 16,000 m/s

E= 27 mV/m

E=0.027 V/m

d= 22.5 cm

d= 0.225 m

a)

lets time taken by electron is t

d = V x t

0.225 = 16,000 t

$t=1.4\times 10^{-5}\ s$

b)

We know that

F = m a = E q ------------1

Mass of electron ,m

$m=9.1\times 10^{-31}\ kg$

Charge on electron

$q=1.6\times 10^{-19}\ C$

So now by putting the values in equation 1

$a=\dfrac{E q}{m}$

$a=\dfrac{1.6\times 10^{-19}\times 0.027}{9.1\times 10^{-31}}\ m/s^2$

$a=4.74\times 10^{9}\ m/s^2$

$S= ut+\dfrac{1}{2}at^2$

Here initial velocity u= 0 m/s

$S= \dfrac{1}{2}\times 4.74\times 10^{9}\times (1.4\times 10^{-5})^2\ m$

S=0.464 m

S= 46.4 cm

S is the deflection of electron.

4 0

4 years ago

Read 2 more answers

HELP PLS i need this right now

N76 [4]

Answer:

V = 44.4 units.

Explanation:

In order to solve this problem, we must use the Pythagorean theorem. Which is defined by the following expression.

$V = \sqrt{(V_{x})^{2} +(V_{y})^{2} }$

where:

Vx = - 43 units

Vy = 11.1 units

Now replacing:

$V=\sqrt{(-43)^{2} +(11.1)^{2} }\\V=44.4 units$

7 0

3 years ago

two boxes sit on a frictionless surface and are in contact with one another. the first box has a mass of 7 kg and the second box

egoroff_w [7]

The acceleration of the boxes depends on the mass and weight.

we have a mass of 7 and 8 kilograms

if it took 25 N force to move box A, then you would take 25 and multiply by 8 then divide by 2.

It will leave you with 100 N.

finally take the sq rt of 100 to get 10

7 0

3 years ago