In rubidium oxide - Rb₂O , the ions are Rb⁺ and O²⁻
Rb is a group one element with one valence electron. To become stable it loses its outer electron to gain a complete outer shell.
Electronic configuration of Rb is - 1s² 2s² 2p⁶ 3s² 3p⁶ 3d¹⁰ 4s² 4p⁶ 5s¹
Once it loses its valence electron the configuration is;
- 1s² 2s² 2p⁶ 3s² 3p⁶ 3d¹⁰ 4s² 4p⁶
The noble gas with this configuration is Krypton - Kr
Oxygen electron configuration is 1s² 2s² 2p⁴
Once it gains 2 electrons the configuration is - 1s² 2s² 3p⁶
The noble gas with this configuration is Neon - Ne
Answer:
strong nuclear force
Explanation:
1, a force that acts on charged particles
2, a force that holds atomic nuclei together
3, gravity, weak nuclear, electromagnetic, strong nuclear
4, strong nuclear force
5, Gravity and the electromagnetic force have infinite ranges while the nuclear forces have very small ranges.
100% :)
Convert the mass to moles .
85.1 g ÷ 20.18 g/mol = 4.21704658
convert the moles to molecules
4.2170 mol × 6.022^23 molecules/mol = 2.539^24
Answer:
Explanation:
A) O2 (non polar covalent)
B) HF (polar covalent)
C) NaCl (because its ionic)
im not 100% sure hope it helps
Taking into account definition of percent yield, the percent yield for the reaction is 76.25%.
<h3>Percent yield</h3>
The percent yield is the ratio of the actual return to the theoretical return expressed as a percentage.
The percent yield is calculated as the experimental yield divided by the theoretical yield multiplied by 100%:
where the theoretical yield is the amount of product acquired through the complete conversion of all reagents in the final product, that is, it is the maximum amount of product that could be formed from the given amounts of reagents.
<h3>Percent yield in this case</h3>
In this case, you know:
- actual yield= 1.22 mol
- theorical yield= 1.60 mol
Replacing in the definition of percent yields:
Solving:
<u><em>percent yield= 76.25%</em></u>
Finally, the percent yield for the reaction is 76.25%.
Learn more about percent yield:
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