Answer:
Angular momentum is conserved if there are no external forces
P1 = P2
I1 ω1 = I2 ω2
ω2 / ω1 = I1 / I2
If the skater pulls their arms in (I2 < I1) then the angular speed must increase for angular momentum to be conserved.
Answer:
<h2>0.94 m/s²</h2>
Explanation:
The acceleration of an object given it's mass and the force acting on it can be found by using the formula
![a = \frac{f}{m} \\](https://tex.z-dn.net/?f=a%20%3D%20%20%5Cfrac%7Bf%7D%7Bm%7D%20%20%5C%5C%20)
m is the mass
f is the force
From the question we have
![a = \frac{150}{160} = \frac{15}{16} \\ = 0.9375](https://tex.z-dn.net/?f=a%20%3D%20%20%5Cfrac%7B150%7D%7B160%7D%20%20%3D%20%20%5Cfrac%7B15%7D%7B16%7D%20%20%5C%5C%20%20%3D%200.9375)
We have the final answer as
<h3>0.94 m/s²</h3>
Hope this helps you
We can approach this in another way.
We know that sin(∅) = height / hypotenuse.
Thus, for x, height is 1 and hypotenuse is 3. Using Pythagoras theorem,
3² = 1² + b²
b = √8
cos(x) = b/hypotenuse
cos(x) = √8 / 3
Now, lets consider y:
sec(y) = 1 / cos(y) = 1 / base / hypotenuse = hypotenuse / base
The hypotenuse is 25 and the base is 24. We again apply Pythagoras theorem to find the third side, which works out to be:
height = 7
sin(y) = height / hypotenuse
sin(y) = 7/25
Now, sin(x + y) =
sin(x)cos(y) + sin(y)cos(x)
= (1/3)(24/25) + (√8 / 3)(7/25)
= 8/25 + 7√8/75
= (24 + 14√2) / 75
thirty one and eight over se
venteen kilogram
Answer:Same
Explanation:
Gravitational Potential energy is the function of height i.e. it is proportional to the height gained by an object or in other words work done against gravity is also gravitational Potential energy
For the same mass, if both attained the same height then gravitational Potential energy of both the friends is equal as it does not depend upon the path taken by the person.