Why does current flow through a circuit?

2 answers:

6 0

WHAT MAKES CURRENT FLOW IN A CIRCUIT? When a wire is connected to battery terminals, electrons flow from negative to positive. Unlike (opposite) charges attract, like (same) charges repel. Electrons have a negative charge—they are repelled from the negative and attracted to the positive.

Ghella [55]3 years ago

3 0

Answer:

Explanation:

cause it do

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You can describe the of an object by saying it is moving in a straight line or it curved

Serga [27]

My answer -

You can tell the speed of a car at any instant by looking at curved path but it does not move with the average speed of any object moving in a straight line.

P.s

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8 0

3 years ago

A 30 kg child sitting 5.0 m from the center of a merry-go-round has a constant speed of 5.0 m/s. while she remains seated in the

expeople1 [14]

Let us say that v is the tangential velocity of the object, a to be the centripetal (which acts towards the center of the circle) acceleration and F as the centripetal force, r to be the radius of the circle and m is mass of the child. 

a = v^2 / r

F = ma = mv^2/r

Applying the given values to the equation:

F=30*(5^2/5) => 30*(25/5) => 30*5 => 150 Newtons

Now work is Force times distance, the distance is simply the circumference of the circle.

d = C = 2 * pi * r = 2 * pi * 5 = 10π m

W = F * d = 150 N * 10π m

W = 1500π J = 4712.39 J

8 0

3 years ago

An arrow of 43 g moving at 84 m/s to the right, strikes an apple at rest. The arrow sticks to the apple and both travel at 16.8

Aloiza [94]

Answer:

The mass of the apple is 0.172 kg (172 g)

Explanation:

The Law Of Conservation Of Linear Momentum

The total momentum of a system of bodies is conserved unless an external force is applied to it. The formula for the momentum of a body with mass m and speed v is

P=mv.

If we have a system of two bodies, then the total momentum is the sum of both momentums:

$P=m_1v_1+m_2v_2$

If a collision occurs and the velocities change to v', the final momentum is:

$P'=m_1v'_1+m_2v'_2$

Since the total momentum is conserved, then:

P = P'

Or, equivalently:

$m_1v_1+m_2v_2=m_1v'_1+m_2v'_2$

If both masses stick together after the collision at a common speed v', then:

$m_1v_1+m_2v_2=(m_1+m_2)v'$

We are given the mass of an arrow m1=43 g = 0.043 kg traveling at v1=84 m/s to the right (positive direction). It strikes an apple of unknown mass m2 originally at rest (v2=0). The common speed after they collide is v'=16.8 m/s.

We need to solve the last equation for m2:

$m_2v_2-m_2v'=m_1v'-m_1v_1$