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igor_vitrenko [27]
3 years ago
13

What is the change in boiling point for a 0.615m solution of Mgl2 in water?

Chemistry
1 answer:
ivanzaharov [21]3 years ago
4 0

Answer :  The change in boiling point is, 0.94^oC

Explanation :

Formula used :

\Delta T_b=i\times K_f\times m

where,

\Delta T_b = change in boiling point = ?

i = Van't Hoff factor = 3 (for MgI₂ electrolyte)

K_f = boiling point constant for water = 0.51^oC/m

m = molality  = 0.615 m

Now put all the given values in this formula, we get

\Delta T_b=3\times (0.51^oC/m)\times 0.615m

\Delta T_b=0.94^oC

Therefore, the change in boiling point is, 0.94^oC

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