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Dvinal [7]
3 years ago
13

Why all traveller prefer to travel easily in the morning and night and not when the sun is hot​

Physics
1 answer:
eduard3 years ago
4 0

Answer:

Travelers prefer to travel in morning because arthat time the temperature ️ is not too hot and they can easily travel here and there without any problem. and they also prefer to travel in night because moderate temperature ....

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BRAINLEST FOR CORRECT ANSWER PLEASE
Nata [24]

Answer:

Sledgehammer A has more momentum

Explanation:

Given:

Mass of Sledgehammer A = 3 Kg

Swing speed = 1.5 m/s

Mass of Sledgehammer B = 4 Kg

Swing speed = 0.9 m/s

Find:

More momentum

Computation:

Momentum = mv

Momentum sledgehammer A = 3 x 1.5

Momentum sledgehammer A = 4.5 kg⋅m/s

Momentum sledgehammer B = 4 x 0.9

Momentum sledgehammer B = 3.6 kg⋅m/s

Sledgehammer A has more momentum

5 0
3 years ago
A 900 kilogram compact car was stopped at a traffic light when an 1800 kilogram luxury sedan struck it from behind the two cars
SOVA2 [1]
The answer is B. 22.7 kg-m/s
7 0
4 years ago
Which of these galaxies would you most likely find at the center of a large cluster of galaxies?
Arada [10]

Answer:

b. a large elliptical galaxy

Explanation:

In elliptical galaxies the stars are grouped in an elliptical shape, it has a low quantity of gas and dust in comparison to spiral galaxies, and its stars belong to an old population, there is not new stellar formation in it.

The stars orbit in a messy way which made to believe that they form from the merger of galaxies.

They are also really massive (around 10^{4} solar masses).

The most massive and luminous can be found in the center of cluster of galaxies.  

4 0
3 years ago
The work function for a metal surface is 4.98 eV. What is the largest wavelength of light in nm that will produce photoelectrons
bulgar [2K]

Answer:\lambda =248.99 nm

Explanation:

Given

Work function\left ( \phi \right )=4.98\approx 1.602\times 10^{-19}\times 4.98

h=6.626\times 10^{-34} J

c=2.998\times 10^8

\phi =\frac{hc}{\lambda }

\lambda =\frac{hc}{\phi }

\lambda =\frac{6.626\times 10^{-34}\times 2.998\times 10^8}{4.98\times 1.602\times 10^{-19}}

\lambda =248.99 nm

3 0
3 years ago
On a hot day, the temperature of a 65,000-L swimming pool increases by 1.20°C. What is the net heat transfer during this heating
vichka [17]

Answer:

326149.2 KJ

Explanation:

The heat transfer toward and object that suffered an increase in temperature can be calculated using the expression:

Q = m*cv*ΔT

Where m is the mass of the object, cv is the specific heat capacity at constant volume, which basically means the amount of heat necessary for a 1kg of water to increase 1C degree in temperatur, and ΔT is the change in temperature.

A 65000 L swimming pool will have a mass of:

65000L *\frac{1m^3}{1000L} * \frac{1000kg}{1m^3} = 65000 kg

The specific heat capacity at constant volume of water is equal to 4.1814 KJ/KgC.

We replace the data and get:

Q = m*cv*ΔT = 65000 kg * 4.1814 KJ/KgC * 1.2°C = 326149.2 KJ

3 0
3 years ago
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