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ANTONII [103]
3 years ago
9

what is known as electronegativity and mention how the electro negativity vary long the periods and down the groups..please i ne

ed answers quickly!​
Chemistry
2 answers:
Kobotan [32]3 years ago
5 0

Answer:

Electronegativity is a measure of an atom's ability to attract shared electrons to itself. On the periodic table, electronegativity generally increases as you move from left to right across a period and decreases as you move down a group.

Natalija [7]3 years ago
4 0
Mark Brainliest please

See below and attached image fir answer


Explanation:
Before I go on, I want to bring up that it's not just electronegativity that is affected as you go across a period or up and down a group. Ionization energy and atomic radius also fluctuate.
Here's a diagram:
images.slideplayer.com
images.slideplayer.com
As you can see, electronegativity increases as you go across a period, while electronegativity decreases as you go down a group. However, if this is true (which it is), we can also say many other factors occur, such as:
As you go across a period from left to right, electronegativity increases, ionization energy increases, and atomic radius decreases. In order for energy to increase, radius must decrease.

As you go up and down a period, electronegativity decreases, ionization energy decreases, and atomic radius increases. In order for energy to decrease, radius must increase.

Electronegativity is the force/energy required to acquire electrons and form negative ions during chemical reactions. (definition credit: from my computers dictionary).

Ionization Energy is the complete opposite. Ionization is the force/energy required to remove electrons from an ion. These strive to make cations while electronegative ions usually involve anions (hence the phrase electronegativity).

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A certain material has a normal freezing point of 10ºC and a normal boiling point of 70ºC. What state is the material in at room
ahrayia [7]

Explanation:

A freezing point is defined as the point in which a liquid state of a substance changes into solid state.

Whereas boiling point is defined as the point at which liquid state of substance starts to convert into vapor state.

So, a substance is freezing at 10^{o}C and boils at 70^{o}C then it means at room temperature, that is, around 25^{o}C the substance is present in liquid state.

This is because between the freezing and boiling point a substance will always exist in liquid state.

Thus, we can conclude that state of the material at room temperature is liquid.

5 0
3 years ago
An object was measured by a worker as
Gre4nikov [31]

Answer:

\boxed{2.8 \, \%}

Explanation:

\text{Percent error} = \dfrac{\lvert \text{Measured - Actual}\lvert}{ \text{Actual}} \times100 \, \%

Data:

Predicted = 17.4 cm

     Actual = 17.9 cm

Calculation:

\text{Percent error} = \dfrac{\lvert 17.4 - 17.9\lvert}{17.9} \times 100 \, \% \\\\= \dfrac{\lvert-0.5\lvert}{17.9} \times 100 \, \% = \dfrac{0.5}{17.9} \times 100 \, \% \\\\= 0.028 \times 100 \, \% = \textbf{2.8 \%}\\\\\text{The percent error in the measurement is } \boxed{\textbf{2.8 \%}}

6 0
3 years ago
Que es un atomo y una molecula?
Setler79 [48]

Answer:

Atom - un átomo de hidrógeno pierde un electrón, adquiere una carga positiva

Molecule - Al aumentar el calor, las moléculas se alejan en mayor medida unas de otras y se intensifica su estado de agitación.

4 0
3 years ago
Today is October 31 and we view or third quarter on what date did we reserve the last new moon
Mrrafil [7]
Answer: March 21

Explanation: March 21
6 0
3 years ago
What is the kinetic energy of the emitted electrons when cesium is exposed to UV rays of frequency 1.80×1015Hz ?
Soloha48 [4]

The kinetic energy of emitted electrons when cesium is exposed to UV rays of frequency 1.80 * 10 ^15 is 3.054 x 10 ^- 19 J.

Explanation:

To calculate the kinetic energy of emitted electrons,

It is given that the frequency is 1.80* 10^15 Hz

We have,

KE = E – Eo = hv –hvo

Where, h = 6.626 x 10^ - 34 Js

Given frequency = 1.4 x 10 ^ 15 Hz

vo (Threshold frequency) for cesium = 9.39 x 10 ^ 14 Hz

Applying in equation,

we get

KE = 6.626 x 10^34 (1.4 x 10^15 - 9.39 x 10^14)

KE= 3.054 x 10^-19 J

[Note: Here, threshold frequency of Cesium is not provided. Apply the correct threshold frequency from the part A]

7 0
3 years ago
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