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ANTONII [103]
3 years ago
9

what is known as electronegativity and mention how the electro negativity vary long the periods and down the groups..please i ne

ed answers quickly!​
Chemistry
2 answers:
Kobotan [32]3 years ago
5 0

Answer:

Electronegativity is a measure of an atom's ability to attract shared electrons to itself. On the periodic table, electronegativity generally increases as you move from left to right across a period and decreases as you move down a group.

Natalija [7]3 years ago
4 0
Mark Brainliest please

See below and attached image fir answer


Explanation:
Before I go on, I want to bring up that it's not just electronegativity that is affected as you go across a period or up and down a group. Ionization energy and atomic radius also fluctuate.
Here's a diagram:
images.slideplayer.com
images.slideplayer.com
As you can see, electronegativity increases as you go across a period, while electronegativity decreases as you go down a group. However, if this is true (which it is), we can also say many other factors occur, such as:
As you go across a period from left to right, electronegativity increases, ionization energy increases, and atomic radius decreases. In order for energy to increase, radius must decrease.

As you go up and down a period, electronegativity decreases, ionization energy decreases, and atomic radius increases. In order for energy to decrease, radius must increase.

Electronegativity is the force/energy required to acquire electrons and form negative ions during chemical reactions. (definition credit: from my computers dictionary).

Ionization Energy is the complete opposite. Ionization is the force/energy required to remove electrons from an ion. These strive to make cations while electronegative ions usually involve anions (hence the phrase electronegativity).

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(a) Given that density is usually expressed in the units of g/cm3
Lena [83]

Answer:

0.690g/cm^3

Explanation:

•Mass: <em>2.331g</em>

•Volume: 3.375 cm^3

One side is 1.5cm.

1.5^3

<em>3.375cm^3</em>

•Density: Mass/Volume

Mass = 2.331g

Volume = 3.375cm^3

2.331g/3.375cm^3

0.690g/cm^3

<h2>Density: 0.690g/cm^3</h2>

8 0
3 years ago
A farmer plants corn in nutrient rich soil. The corn plants absorb nutrients from the soil in order to grow and perform life pro
ratelena [41]

Answer:

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3 years ago
A pharmacy intern is asked to prepare 3 L of a 30% w/v solution. T he pharmacy stocks the active ingredient in 8-ounce bottles o
MariettaO [177]

<u>Answer:</u> The number of bottles that will be needed are 6

<u>Explanation:</u>

We are given:

Amount of solution, the intern is asked to prepare = 3 L = 3000 mL   (Conversion factor:  1 L = 1000 mL)

Strength of solution needed = 30 % (w/v)

This means that in 100 mL of solution, the solute present is 30 grams

So, in 3000 mL of solution, the solute present will be = \frac{30}{100}\times 3000=900g

Active ingredient present in 1 bottle = 8 ounce of 70 % (w/v)

<u>Conversion factor used:</u> 1 ounce = 29.57 mL

So, 8ounce\times \frac{29.57mL}{1ounce}=236.6mL

Amount of active ingredient present in 1 bottle = 236.6\times \frac{70}{100}=165.6g

To calculate the number of bottles, we need to divide the total amount of solution needed by the amount of active ingredient present in 1 bottle, we get:

\text{Number of bottles}=\frac{\text{Amount of solution to prepare}}{\text{Amount of active ingredient in 1 bottle}}

Putting values in above equation, we get:

\text{Number of bottles}=\frac{900g}{165.6g}\\\\\text{Number of bottles}=5.43\approx 6

Hence, the number of bottles that will be needed are 6

6 0
3 years ago
For a solution of H2SO4, determine the van\'t Hoff factor assuming 0% ionization and 100% ionization
Aleks [24]
The van't Hoff factor is the ratio between the amount of particles produced when a substance is dissolved and the amount of substance being dissolved. If ionization is 0 percent then it would mean that the substance do not dissociate into particles so the van't Hoff factor would be 1. However, when the percent ionization is 100%, then it fully dissociates into ions. For H2SO4 at 100% ionization, the vant hoff factor should be three, two hydrogen ions and one sulfate ion.
7 0
3 years ago
Read 2 more answers
A gas sample has volume 3.00 dm3 at 101
gavmur [86]

Answer:

V₂ = 21.3 dm³

Explanation:

Given data:

Initial volume of gas = 3.00 dm³

Initial pressure = 101 Kpa

Final pressure = 14.2 Kpa

Final volume = ?

Solution;

The given problem will be solved through the Boly's law,

"The volume of given amount of gas is inversely proportional to its pressure by keeping the temperature and number of moles constant"

Mathematical expression:

P₁V₁ = P₂V₂

P₁ = Initial pressure

V₁ = initial volume

P₂ = final pressure

V₂ = final volume  

Now we will put the values in formula,

P₁V₁ = P₂V₂

101 Kpa × 3.00 dm³ = 14.2 Kpa × V₂

V₂ = 303 Kpa. dm³/  14.2 Kpa

V₂ = 21.3 dm³

Explanation:

3 0
3 years ago
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